Answer- im pretty sure it's 2
Answer:
(a) The proportion of dry air bypassing the unit is 14.3%.
(b) The mass of water removed is 1.2 kg per 100 kg of dry air.
Explanation:
We can express the proportion of air that goes trough the air conditioning unit as
and the proportion of air that is by-passed as
, being
.
The amount of water that goes into the drier inlet has to be 0.004 kg/kg, and can be expressed as:

Replacing the first equation in the second one we have

(b) Of every kg of dry air feed, 85.7% goes in to the air conditioning unit.
It takes (0.016-0.002)=0.014 kg water per kg dry air feeded.
The water removed of every 100 kg of dry air is

It can also be calculated as the difference in humiditiy between the inlet and the outlet: (0.016-0.004=0.012 kgW/kDA) and multypling by the total amount of feed (100 kgDA).
100 * 0.012 = 1.2 kgW
Answer:
c.
Explanation:
not to positive but I hope this is correct ♀️
Answer:
8.38×10raise to power 23
Explanation:
mass of sugar=density ×volume
=. 1.59g/ml×25ml=39.75
no. of miles= given mass/ molar mass
= 39.75/342.3g / mole
1 mole of sugar =C12 H22 O11
contains
12× 6.023 × 10 ∆23=72.28× 10∆ 23 ×6.023×10²³
= 8.38× 10²³
An atom has an average atomic mass of about 63.5 amu.
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1 amu is equal to 1 gram per mole
so 63.5 amu is just equal to 63.5 grams per mole or 63.5 g/mol
the answer is Cu or copper.
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