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melomori [17]
3 years ago
7

The speeds of 22 particles are as follows: two at 5.30 cm/s, four at 1.40 cm/s, six at 7.14 cm/s, eight at 1.52 cm/s, two at 7.6

8 cm/s. What are (a) vavg, (b) vrms, and (c) vP?
Physics
1 answer:
Leona [35]3 years ago
8 0

Answer:

Average velocity is 3.93 cm/s

Root mean square velocity is 4.79 cm/s

Velocity peak to peak is 6.28 cm/s

Explanation:

Speed of 2 particles = 5.3 cm/s

Speed of 4 particles = 1.4 cm/s

Speed of 6 particles = 7.14 cm/s

Speed of 8 particles = 1.52 cm/s

Speed of 2 particles = 7.68 cm/s

v_{avg}=\frac{2\times 5.3+4\times 1.4+6\times 7.14+8\times 1.52+2\times 7.68}{22}\\\Rightarrow v_{avg}=\frac{86.56}{22}\\\Rightarrow v_{avg}=3.93\ cm/s

Average velocity is 3.93 cm/s

v_{rms}=\sqrt{\frac{2\times 5.3^2+4\times 1.4^2+6\times 7.14^2+8\times 1.52^2+2\times 7.68^2}{22}}\\\Rightarrow v_{rms}=\sqrt{\frac{507.34}{22}}\\\Rightarrow v_{rms}=4.79\ cm/s

Root mean square velocity is 4.79 cm/s

v_p=7.68-1.4=6.28\ cm/s

Velocity peak to peak is 6.28 cm/s

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A body of mass 5.0 kg is suspended by a spring which stretches 10 cm when the mass is attached. It is then displaced downward an
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Answer:

position as a function of time is y = 0.05 × cos(9.9)t

Explanation:

given data

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to find out

position as a function of time

solution

we will apply here equilibrium that is

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and ω is

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so here position w.r.t  time is

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Explanation:

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Not the question is asking what is the total momentum of the football player and uniform. So we need to first get the combined mass of the football player and the uniform. 

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