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Tom [10]
3 years ago
7

Wich has a larger percent by mass of sulfur - H2SO or H2S7O8?

Chemistry
1 answer:
Pie3 years ago
5 0

Answer:

Explanation:

H2SO4 let S be x

2(1) + x + 4(-2) = 0

2 + x - 8 = 0

x - 6 = 0

x = 6

For H2S7O8 let S be x

2(1) + 7(x) + 8(-2) = 0

2 + 7x - 16 = 0

7x - 14 = 0

7x = 14

x = 14/7

x = 2

:- H2SO4 as the larger percentage

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How many atoms of gold are in gold nugget with a mass of 4.25 g
Feliz [49]
Number of Atoms in Gold for given mass can be calculated using following formula,

              # of Moles  =  Number of Atoms / 6.022 × 10²³
Or,
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Calculating Moles,
As,
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heya!!!

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(it's alre answered but here it again 'NOTE: not my answer')

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2 years ago
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