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DaniilM [7]
3 years ago
7

In garden peas٫round seed coats (R) Is a dominant over wrinkled seed coats (r). What will the result be of a cross between a het

erozygous male (Rr) and a heterozygous female (Rr). Use a punnett square
Chemistry
1 answer:
8090 [49]3 years ago
3 0

Answer:

Image attached, please give thanks

Explanation:

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Pollen is transferred from the stamen of one flower to the stigma of another. What has occurred?
Digiron [165]
Cross-pollination is the transfer of pollen from the anther of one flower to the stigma of another flower on a different individual of the same species. Self-pollination occurs in flowers where the stamen and carpel mature at the same time, and are positioned so that the pollen can land on the flower's stigma.
3 0
3 years ago
Read 2 more answers
I WILL MARK BRAINLISET FOR WHOEVER GETS THIS RIGHT! A pot is placed on a gas flame, and the water inside the pot begins to boil.
NNADVOKAT [17]

Answer:

B.     Warm water rises within the pot.?

Explanation

<em>There wasn't enough information given for me to safely determine the correct answer.</em>

8 0
3 years ago
Consider separate solutions of NaOH and KClmade by dissolving 100.0 g of each solute in 250.0 mL of solution. Calculate the conc
gladu [14]

Answer:

Explanation:

MW of NaOH = 40 g/mol

MW of KCl = 74.55 g/mp;

250 mL = .25 L

100g NaOH / 40 g = 25 mol

100g KCl/ 74.55g = 1.34 mol

Molarity of NaOH: 25/.25 = 100M

Molarity of KCl: 1.34/.25 = 5.36 M

8 0
3 years ago
At a given temperature the vapor pressures of hexane and octane are 183 mmhg and 59.2 mmhg, respectively. Calculate the total va
Bas_tet [7]

Total vapor pressure can be calculated using partial vapor pressures and mole fraction as follows:

P=X_{A}P_{A}+X_{B}P_{B}

Here, X_{A} is mole fraction of A, X_{B} is mole fraction of B, P_{A} is partial pressure of A and P_{B} is partial pressure of B.

The mole fraction of A and B are related to each other as follows:

X_{A}+X_{B}=1

In this problem, A is hexane and B is octane, mole fraction of hexane is given 0.580 thus, mole fraction of octane can be calculated as follows:

X_{octane}=1-X_{hexane}=1-0.58=0.42

Partial pressure of hexane and octane is given 183 mmHg and 59.2 mmHg respectively.

Now, vapor pressure can be calculated as follows:

P=X_{hexane}P_{hexane}+X_{octane}P_{octane}

Putting the values,

P=(0.580)(183 mmHg)+(0.420)(59.2 mmHg)=131 mmHg

Therefore, total vapor pressure over the solution of hexane and octane is 131 mmHg.

4 0
3 years ago
Determine the number of grams of sodium carbonate needed to prepare 100.0 ml of a 2.5 m solution
SCORPION-xisa [38]

Answer:

26.5 g

Explanation:

First we convert 100.0 mL to L:

  • 100.0 mL / 1000 = 0.100 L

Now we <u>calculate how many moles of sodium carbonate are needed</u>, using the <em>definition of molarity</em>:

  • Molarity = moles / liters
  • moles = molarity * liters
  • 2.5 M * 0.100 L = 0.25 mol

Finally we <u>convert 0.25 moles of sodium carbonate into grams</u>, using its <em>molar mass</em>:

  • 0.25 mol * 106 g/mol = 26.5 g
6 0
2 years ago
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