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3 years ago

What is the mass of silver in 4.3g AgNO3?

1 answer:

5 0

4.22 grams.
1. First find out how much AgNO3 weighs with one mole (107.87 g Ag + 14.007 g N + 48 g O = 169.89 grams)
2. Find the percent of Ag you have. So, (107.87 g/mol Ag)/(169.89 g/mol AgNO3)= 0.63 * 100 = 63%.
3. If you have 6.7 grams total, you know 63% of it is going to be silver, so just multiply 6.7 grams by .63 and you get 4.22 g Ag

You might be interested in

How many milliliters of 0.260 m na2s are needed to react with 35.00 ml of 0.315 m agno3?

allochka39001 [22]

The complete balanced chemical reaction is:

2 AgNO3 + Na2S --> 2 NaNO3 + Ag2S

First let us calculate the number of moles of AgNO3.

moles AgNO3 = 0.315 M * 0.035 L

moles AgNO3 = 0.011025 mol

From the reaction, 1 mole of Na2S is needed for every 2 moles of AgNO3 hence:

moles Na2S required = 0.011025 mol AgNO3 * (1 mol Na2S / 2 mol AgNO3)

moles Na2S required = 5.5125 x 10^-3 mol

Therefore volume required is:

volume Na2S = 5.5125 x 10^-3 mol / 0.260 M

volume Na2S = 0.0212 L = 21.2 mL

6 0

3 years ago

Use your Cabbage pH Indicator Key to determine the pH of each. Enter the pH ranges into the data table.

notsponge [240]

Answer: pH :1-2 / acid

pH:7/neutral

pH:8-9/basic

Your welcome

4 0

3 years ago

Read 2 more answers

If 2.00 moles of H₂ and 1.55 moles of O₂ react how many moles of H₂O can be produced in the reaction below?

jekas [21]

Answer:

2 mol H₂O

Explanation:

With the reaction,

2H₂(g) + O₂(g) → 2 H₂O(g)

1.55 moles of O₂ would react completely with ( 2*1.55 ) 3.1 moles of H₂. There are not as many moles of H₂, thus H₂ is the limiting reactant.

Now we calculate the moles of H₂O produced, starting from the moles of limiting reactant:

2.00 mol H₂ * $\frac{2molH_2O}{2mol H_2}$ = 2 mol H₂O

5 0

2 years ago

What is the mass of 1.75 moles of magnesium atoms

Artemon [7]

Hey there!

Molar mass of magnesium is 24.305.

One mole of magnesium has a mass of 24.305 grams.

We have 1.75 moles.

Multiply 1.75 by 24.305.

1.75 x 24.305 = 42.5

1.75 moles of magnesium has a mass of 42.5 grams.

Hope this helps!

6 0

2 years ago

What is the volume of 220 grams of an object with a density of 55g/cm square

AnnyKZ [126]

I'm assuming that you meant 55 g/cm^3. Density= $\frac{Mass}{Volume}$ . This is the definition of density. If you rearrange this equation by multiplying each side of the equation by the volume, you get: (Density)(Volume)=Mass. Divide each side by the density to get: Volume=Mass/Density. Now just plug everything in:
V=220 (grams)/55 (grams/cm^3)=4 cm^3

4 0

3 years ago