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telo118 [61]
3 years ago
13

What is the mass of silver in 4.3g AgNO3?

Chemistry
1 answer:
gregori [183]3 years ago
5 0
4.22 grams.
1. First find out how much AgNO3 weighs with one mole (107.87 g Ag + 14.007 g N + 48 g O = 169.89 grams)
2. Find the percent of Ag you have. So, (107.87 g/mol Ag)/(169.89 g/mol AgNO3)= 0.63 * 100 = 63%.
3. If you have 6.7 grams total, you know 63% of it is going to be silver, so just multiply 6.7 grams by .63 and you get 4.22 g Ag
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Mashutka [201]

Answer:

The correct answer is - adrenal medulla.

Explanation:

The adrenal medulla is the internal part of the the adrenal gland that is the controlled by the sympathetic nervous system, Adrenal medulla is part of the adrenal gland where different molecules act as the hormones.

Adrenal medulla include various hormones as secreted hormones from there.  Fight or flight is also initiate by the hormones secreted from adrenal gland that are epinephrine, nor epinephrine.

Thus, the correct answer is - adrenal gland.

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A ________ sample of urine is the type of urine specimen most commonly collected.
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svetoff [14.1K]

Answer:

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4 years ago
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K2Te+ Fe(HCO3)2------&gt; KHCO3 + Fe Te<br> how do you balance the equation?
ololo11 [35]

Hey there!

K₂Te + Fe(HCO₃)₂ → KHCO₃ + Fe + Te

Start by balancing HCO₃ since it's a polyatomic ion.

Two on the left, one on the right. Add a coefficient of 2 in front of KHCO₃.

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Balance K .

Two on the left, two on the right. Already balanced.

Balance Te.

One on the left, one on the right. Already balanced.

Balance Fe.

One on the left, one on the right. Already balanced.

Our final balanced equation:

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Hope this helps!

4 0
3 years ago
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Here's the Answer !

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3 years ago
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