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Llana [10]
4 years ago
13

1. If in the following diagram the substance is in solid form during stage 1, at what stage do the particles have no intermolecu

lar bonding?
(THERE IS A PIC AND IT'S THE FIRST ONE!!!)
1
3
5
Intermolecular bonding occurs during all stages.
2. Which of the following equations is not balanced?

N2 + 3H2 → 2NH3
MgI2 + Br2 → MgBr2 + I2
KClO3 → KCl + O2
HCl + NaOH → NaCl + H2O
3. In the alpha decay of Polonium-218, what daughter element is produced?
(PIC IS PIC 2)
4. Using the general equation above for a nuclear reaction, supply the following answer:
(PIC IS PIC 3)
There are (96,146,242) curium neutrons.

Chemistry
2 answers:
natima [27]4 years ago
6 0
1. Stage 5 (Gas). 2. The 3rd equation is not balanced. There are only 2 Os on the right side of the equation whereas there were 3 Os on the left side.3. The correct answer is the 3rd option (214, 82 Pb)4. There are 146 curium neutrons.
Mama L [17]4 years ago
6 0

Answer:

the answer is 5

Explanation:

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NNADVOKAT [17]

Answer:

Al2o3 is 101

(nh4)2O IS 52

S8 is 256.56

Ba(oh)2 is 171.35

Cacl2 is 110.98

H2O is 18.01

Explanation:

5 0
3 years ago
In a car crash, large accelerations of the head can lead to severe injuries or even death. A driver can probably survive an acce
Alexxandr [17]

Answer:

Velocity, u = 14.7 m/s

Explanation:

It is given that, a driver can probably survive an acceleration of 50 g that lasts for less than 30 ms, but in a crash with a 50 g acceleration lasting longer than 30 ms, a driver is unlikely to survive.

Let v is the highest speed that the car could have had such that the driver survived. Using a = -50 g and t = 30 ms

Using first equation of kinematics as :

v=u+at

In case of crash the final speed of the driver is, v = 0

0=u+at

-u=at

-u=-50\times 9.8\times 30\times 10^{-3}

u = 14.7 m/s

So, the highest speed that the car could have had such that the driver survived is 14.7 m/s. Hence, this is the required solution.

8 0
3 years ago
Imagine you are and astronaut returning to Earth from a space mission to Mars. In which order would you pass through the layers
mafiozo [28]
It is C. That is the answer. Mate rate 8/8
4 0
3 years ago
Read 2 more answers
A solution is made by dissolving 0.611 mol of NaCl in 250 g of water. If the molar mass of NaCl is 58.44 g/mol, what is the mola
shusha [124]
Molality= moles NaCl/ Kg H2O

250 g (1 Kg/ 1000 grams)= 0.250 Kg

Molality= 0.611 moles/ 0.250 Kg= 2.44 molal
6 0
3 years ago
Read 2 more answers
Consider a 125 mL buffer solution at 25°C that contains 0.500 mol of hypochlorous acid (HOCl) and 0.500 mol of sodium hypochlori
Helga [31]

Answer:

pH = 6.82

Explanation:

To solve this problem we can use the<em> Henderson-Hasselbach equation</em>:

  • pH = pKa + log\frac{[NaOCl]}{[HOCl]}

We're given all the required data to <u>calculate the original pH of the buffer before 0.341 mol of HCl are added</u>:

  • pKa = -log(Ka) = -log(2.9x10⁻⁸) = 7.54
  • [HOCl] = [NaOCl] = 0.500 mol / 0.125 L = 4 M
  • pH = 7.54 + log \frac{4}{4}
  • pH = 7.54

By adding HCl, w<em>e simultaneously </em><u><em>increase the number of HOCl</em></u><em> and </em><u><em>decrease NaOCl</em></u>:

  • pH = 7.54 + log\frac{[NaOCl-HCl]}{[HOCl+HCl]}
  • pH = 7.54 + log \frac{(0.500mol-0.341mol)/0.125L}{(0.500mol+0.341mol)/0.125L}
  • pH = 6.82
6 0
3 years ago
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