1. If in the following diagram the substance is in solid form during stage 1, at what stage do the particles have no intermolecu
lar bonding?
(THERE IS A PIC AND IT'S THE FIRST ONE!!!)
1
3
5
Intermolecular bonding occurs during all stages.
2. Which of the following equations is not balanced?
N2 + 3H2 → 2NH3
MgI2 + Br2 → MgBr2 + I2
KClO3 → KCl + O2
HCl + NaOH → NaCl + H2O
3. In the alpha decay of Polonium-218, what daughter element is produced?
(PIC IS PIC 2)
4. Using the general equation above for a nuclear reaction, supply the following answer:
(PIC IS PIC 3)
There are (96,146,242) curium neutrons.
(THERE IS A PIC AND IT'S THE FIRST ONE!!!)
1
3
5
Intermolecular bonding occurs during all stages.
2. Which of the following equations is not balanced?
N2 + 3H2 → 2NH3
MgI2 + Br2 → MgBr2 + I2
KClO3 → KCl + O2
HCl + NaOH → NaCl + H2O
3. In the alpha decay of Polonium-218, what daughter element is produced?
(PIC IS PIC 2)
4. Using the general equation above for a nuclear reaction, supply the following answer:
(PIC IS PIC 3)
There are (96,146,242) curium neutrons.
2 answers:
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The value of ΔG° at this temperature is -18034.18 J/mol
Calculation,
Given information
formation constant (Kf)= 1.7 ×
Universal gas constant (R) = 8.314 J/K• mol
Temperature = 25° C = 25 °C + 273 = 300 K
Formula used:
ΔG° = -RT㏑Kf
By putting the valur of R,T, Kf we get the value of ΔG°
ΔG° = - 8.314 J/K• mol×300K㏑ 1.7 ×
ΔG° = -2494.2㏑ 1.7 × = -18034.18 J/mol
So, change in standard Gibbs's free energy is -18034.18 J/mol
Learn about formation constant
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