Answer:
Here's what I get
Explanation:
The reaction is an E1 elimination of an alcohol to form an alkene. It has three steps:
1. Protonation
The alcohol is protonated with aqueous sulfuric acid to convert it into a better leaving group.
2. Loss of the leaving group
A water molecule leaves in a unimolecular process to form a stable 3° carbocation.
3. Loss of an α-hydrogen
A water molecule removes an α-hydrogen, forming 2-methylpropene and regenerating the original hydronium ion.
