<span>Most low-level radioactive waste (LLW) is typically sent to land-based disposal immediately following its packaging for long-term management. This means that for the majority (~90% by volume) of all of the waste types produced by nuclear technologies, a satisfactory disposal means has been developed and is being implemented around the world.
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Radioactive wastes are stored so as to avoid any chance of radiation exposure to people, or any pollution.The radioactivity of the wastes decays with time, providing a strong incentive to store high-level waste for about 50 years before disposal.Disposal of low-level waste is straightforward and can be undertaken safely almost anywhere.Storage of used fuel is normally under water for at least five years and then often in dry storage.<span>Deep geological disposal is widely agreed to be the best solution for final disposal of the most radioactive waste produced.
</span>I suggest this site on this subject http://www.world-nuclear.org/information-library/nuclear-fuel-cycle/nuclear-wastes/storage-and-dispo...
        
             
        
        
        
1935.5 N is the "net force" acting on a car.
<u>Explanation</u>:
Given that,  
Mass of the car is 790 kg.
Velocity of the car is 7 m/s. (v)
It turned around with 20 m. (r)  
We know that, Net force = m × a




Now, Net force = m × a
Net force = 790 × 2.45
Net force = 1935.5 N
 
        
             
        
        
        
Answer:
a = F/m
Explanation:
So we have to isolate a, in order to do this we need to move m to the other side, and we do that by diving both sides by m, resulting in a = F/m
 
        
             
        
        
        
Answer:
  K_a = 8,111 J
Explanation:
This is a collision exercise, let's define the system as formed by the two particles A and B, in this way the forces during the collision are internal and the moment is conserved
initial instant. Just before dropping the particles
           p₀ = 0
final moment
           p_f = m_a v_a + m_b v_b
           p₀ = p_f
           0 = m_a v_a + m_b v_b
tells us that
           m_a = 8 m_b
          
            0 = 8 m_b v_a + m_b v_b
            v_b = - 8 v_a                    (1)
indicate that the transfer is complete, therefore the kinematic energy is conserved
starting point
            Em₀ = K₀ = 73 J
final point. After separating the body
           Em_f = K_f = ½ m_a v_a² + ½ m_b v_b²
            K₀ = K_f
            73 = ½ m_a (v_a² + v_b² / 8)
            
we substitute equation 1
            73 = ½ m_a (v_a² + 8² v_a² / 8)
            73 = ½ m_a (9 v_a²)
            73/9 = ½ m_a (v_a²) = K_a
             K_a = 8,111 J
 
        
             
        
        
        
Answer:
HOPE IT HELPS..... 
Explanation:
The legal standard for drunkenness across the United States ranges from 0.10 to 0.08. If a person's BAC measures 0.08, it means that there are 0.08 grams (i.e., 80 mg) of alcohol per 100 ml of blood. The American Medical Association says that a person can become impaired when the blood alcohol level hits 0.05.