Answer:
Red
Explanation:
I looked at the picture...where it says red is 700
The coefficient of friction is 0.051
Explanation:
The motion of the skater is a uniformly accelerated motion, therefore we can use the following suvat equation:
where:
v = 0 is the final velocity of the skater (he comes to a stop)
u = 10.0 m/s is his initial velocity
a is the acceleration
is the distance he travels before stopping
Solving for a, we find the acceleration of the skater:
We also know that the net force acting on the skater is the force of friction, therefore we can write (Newton's second law of motion):
where
is the force of friction
m is the mass of the skater
is the coefficient of friction
is the acceleration
is the acceleration of gravity
Solving for , we find the coefficient of friction:
Learn more about friction:
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Answer:
A)t=<u>1.375s</u>
B)t=11s
Explanation:
for this problem we will assume that the east is positive while the west is negative, what we must do is find the relative speed between the wave and the powerboat, and then with the distance find the time for each case
ecuations
V=Vw-Vp (1)
V= relative speed
Vw= speed of wave
Vp=Speesd
t=X/V(2)
t=time
x=distance=44m
A) the powerboat moves to west
V=18-(-14)=32m/s
t=44/32=<u>1.375s</u>
B)the powerboat moves to east
V=18-14=4
t=44/4=<u>11s</u>
Answer:
Broglie wavelength: electron 1.22 10⁻¹⁰ m
, proton 2.87 10⁻¹² m
, hydrogen atom 7.74 10⁻¹² m
Explanation:
The equation given by Broglie relates the momentum of a particle with its wavelength.
p = h /λ
In addition, kinetic energy is related to the amount of movement
E = ½ m v²
p = mv
E = ½ p² / m
p = √2mE
If we clear the first equation and replace we have left
λ = h / p =
λ = h / √2mE
Let's reduce the values that give us SI units
1 ev = 1,602 10⁻¹⁹ J
E1 = 100 eV (1.6 10⁻¹⁹ J / 1eV) = 1.6 10⁻¹⁷ J
We look in tables for the mass of the particle and the Planck constant
h = 6,626 10-34 Js
me = 9.1 10-31 Kg
mp = 1.67 10-27 Kg
Now let's replace and calculate the wavelengths
a) Electron
λ1 = 6.6 10⁻³⁴ / √(2 9.1 10⁻³¹ 1.6 10⁻¹⁷) = 6.6 10⁻³⁴ / 5.39 10⁻²⁴
λ1 = 1.22 10⁻¹⁰ m
b) Proton
λ2 = 6.6 10-34 / √(2 1.67 10⁻²⁷ 1.6 10⁻¹⁷) = 6.6 10⁻³⁴ / 2.3 10⁻²²
λ2 = 2.87 10⁻¹² m
c) Bohr's first orbit
En = 13.606 / n2 [eV]
n = 1
E1 = 13.606 eV
E1 = 13,606 ev (1.6 10⁻¹⁹ / 1eV) = 21.77 10⁻¹⁹ J
λ3 = 6.6 10⁻³⁴ /√(2 1.67 10⁻²⁷ 21.77 10⁻¹⁹) = 6.6 10⁻³⁴ / 8.52 10⁻²³
λ3 = 0.774 10⁻¹¹ m = 7.74 10⁻¹² m
Answer:
a)1.14
b)0.31
c)1.14
d)0.25
Explanation:
Assume wave travels in a harmonic motion. This means if it takes 2.8 for the boat to travel from highest to lowest point, then it'd take 2.8*2 = 5.6 for the boat to travel in 1 period (from highest point to lowest point then back to highest point again).
a)As the wave crest is 6.4 apart. Then it's speed is
v = s/t = 6.4/5.6 = 1.14
b) The amplitude would be half of the vertical distance traveled by the boat, which is
A = 0.62 / 2 = 0.31
c) As the distance between the crest and the time it takes for the boat to travel vertically is unchanged, then the wave speed would stay the same:
v = 1.14
d) The amplitude would again be half of the vertical distance
A = 0.5 / 2 = 0.25
