What is the impulse of a 3kg object accelerating from rest to 12m/s?

1 answer:

6 0

To find the impulse you multiply the mass by the change in velocity (impulse=mass×Δvelocity). So in this case, 3 kg × 12 m/s ("12" because the object went from zero m/s to 12 m/s).

The answer is 36 kg m/s

You might be interested in

A thin film soap bubble (n=1.35) is floating in air. If the thickness of the bubble wall is 300nm, which of the following wavele

iren [92.7K]

Answer:

540 nm

Explanation:

According to the question,

The refractive index of the soap bubble, $n=1.35$ .

The thickness of the soap bubble wall is, $t=300 nm$ .

Now, for constructive interference of soap bubble.

$2nt=(m+\frac{1}{2})\lambda$ .

Now for first order m=1.

Therfore,

$\lambda =\frac{4}{3} tn$

Substitute all the variables in the above equation.

$\lambda =\frac{4}{3} (1.35)(300 nm)$ .

Therefore,

$\lambda =540 nm$ .

Therefore the visible light wavelength which is strongly reflected is 540 nm.

6 0

3 years ago

The gravitational force between two objects is f. If masses of both objects are halved without changing distance between them, t

Marrrta [24]

The gravitation force is quartered when two objects' masses are halved without changing their distance.

Gravitational law states that the force of attraction and repulsion between two objects is directly proportional to the product of their masses and inversely proportional to the square of their distance apart.

F=(KM1 M2)/r^2

K= Gravitation force constant

M1M2 = masses of the object

r = distance between objects

When M1 and M2 are halved, it becomes M1/2 and M2/2

F=(K M1/2 x M2/2)/r^2

F=(K (M1 x M2)/4)/r^2

F=(KM1 x M2)/(4r^2 )

Recall

F=(KM1 x M2)/r^2

Therefore

F=F/4