1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zysi [14]
4 years ago
6

How is data used to make predictions or defend conclusions in science?

Chemistry
2 answers:
Jet001 [13]4 years ago
4 0
Data can help your predictions and conclusions more accurate.
djyliett [7]4 years ago
3 0

Answer:

it can be used to help answer

Explanation:

You might be interested in
The frequency, wavelength, and amplitude of a simple wave can best be described as what?
stich3 [128]
The waves can be described as a pattern
3 0
4 years ago
Read 2 more answers
A sample of hydrogen was collected by water displacement at 23.0°C and an atmospheric pressure of 735 mmHg. Its volume is 568 mL
ziro4ka [17]

Answer:

V = 552 mL or 0.552 L

Explanation:

First, we need to calculate the number of moles of H2 using the ideal gas equation which is:

PV = nRT

Solving for n:

n = PV / RT

Where:

P = Pressure

V = Volume

R = Gas constant (0.082 L atm / K mol)

T = Temperature in K

Let's convert first both pressure in atm, remember that 1 atm = 760 mmHg

P = 735 / 760 = 0.967 atm

Pwater = 21 / 760 = 0.028 atm

Finally temperature to Kelvin:

T = 23 + 273.15 = 296.15 K

Now, at first the hydrogen was collected by water displacement so pressure is:

P = 0.967 - 0.028 = 0.939 atm

Now the moles of hydrogen:

n = 0.939 * 0.568 / 0.082 * 296.15

n = 0.022 moles

Now that we have the moles, let's calculate the volume when the pressure is 735 mmHg

V = nRT/P

V = 0.022 * 0.082 * 296.15 / 0.967

V = 0.552 L or 552 mL

This is the volume that hydrogen occupies.

6 0
3 years ago
A chemist prepares a solution by adding 258 mg of K2Cr2O7 (MW = 294.19 g/mol ) to a volumetric flask, and then adding water unti
Maksim231197 [3]

Answer: Molarity of the prepared solution is 1.75\times 10^{-3}mole/L

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute

V_s = volume of solution in ml = 500 ml

moles of solute =\frac{\text {given mass}}{\text {molar mass}}=\frac{0.258g}{294.19g/mol}=8.77\times 10^{-4}mol

Now put all the given values in the formula of molarity, we get

Molarity=\frac{8.77\times 10^{-4}moles\times 1000}{500ml}=1.75\times 10^{-3}mole/L

Thus molarity of the prepared solution is 1.75\times 10^{-3}mole/L

3 0
3 years ago
A 0.1 m solution of which salt is the most basic? (a) nano3 (b) naclo4 (c) nahso4 (d) nahco
lbvjy [14]
Answer is: d) NaHCO₃ - sodium hydrogen carbonate or s<span>odium bicarbonate.
It is because other salt are made in reaction between strong base and strong acid and </span>sodium hydrogen carbonate is made from strong base (sodium hydroxide) and weak acid (carbonic acid).
Sodium bicarbonate<span> is an aqueous solution is used for cases of </span><span>acidosis.</span>
3 0
3 years ago
At 25 ∘ C , the equilibrium partial pressures for the reaction 3 A ( g ) + 4 B ( g ) − ⇀ ↽ − 2 C ( g ) + 3 D ( g ) were found to
VMariaS [17]

<u>Answer:</u> The standard Gibbs free energy of the given reaction is 6.84 kJ

<u>Explanation:</u>

For the given chemical equation:

3A(g)+4B(g)\rightleftharpoons 2C(g)+3D(g)

The expression of K_p for above equation follows:

K_p=\frac{(p_C)^2\times (p_D)^3}{(p_A)^3\times (p_B)^4}

We are given:

(p_A)_{eq}=5.70atm\\(p_B)_{eq}=4.00atm\\(p_C)_{eq}=4.22atm\\(p_D)_{eq}=5.52atm

Putting values in above expression, we get:

K_p=\frac{(4.22)^2\times (5.52)^3}{(5.70)^3\times (4.00)^4}\\\\K_p=0.0632

To calculate the equilibrium constant (at 25°C) for given value of Gibbs free energy, we use the relation:

\Delta G^o=-RT\ln K_{eq}

where,

\Delta G^o = standard Gibbs free energy = ?

R = Gas constant = 8.314 J/K mol

T = temperature = 25^oC=[273+25]K=298K

K_{eq} = equilibrium constant at 25°C = 0.0632

Putting values in above equation, we get:

\Delta G^o=-(8.314J/Kmol)\times 298K\times \ln (0.0632)\\\\\Delta G^o=6841.7J=6.84kJ

Hence, the standard Gibbs free energy of the given reaction is 6.84 kJ

6 0
4 years ago
Other questions:
  • Classify each of the following properties by writing physical or chemical matter
    12·1 answer
  • There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In
    6·1 answer
  • How many moles of glucose molecules?​
    13·1 answer
  • This is a force that acts over a distance, can not be seen, and causes like poles to repel and opposite poles to attract. What i
    12·2 answers
  • How many moles of NH3 are in 0.350 L of a 5.00 M aqueous solution? mol
    14·1 answer
  • 1a.calculate the relative formula mass of magnesium oxide when the relative atomic masses are O=16 Mg=24
    12·1 answer
  • Help asap please i’m really struggling
    8·1 answer
  • Force exerted on a lever is applied on the<br> lever's
    15·1 answer
  • 50.0 g of nitrogen gas (N2 ) are kept under pressure in a 3.00 L container. If the pressure is kept constant, how many moles of
    12·1 answer
  • In a nuclear fission reaction, a freely moving neutron is introduced to a nuclear fuel, such
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!