Match each example to its type of energy.

Elodia [21]

It will be moving at high speeds

5 0

3 years ago

A 70.0 kg70.0 kg ice hockey goalie, originally at rest, has a 0.170 kg0.170 kg hockey puck slapped at him at a velocity of 41.5

Elza [17]

Answer:

0.2012 m/s

- 41.3 m/s

Explanation:

M = mass of ice hockey goalie = 70 kg

V = initial velocity of the hockey goalie = 0 m/s

V' = final velocity of hockey goalie after collision = ?

m = mass of hockey puck = 0.170 kg

v = initial velocity of hockey puck = 41.5 m/s

v' = final velocity of hockey puck = ?

Using conservation of momentum

M V + m v = M V' + m v'

(70) (0) + (0.170) (41.5) = (70) V' + (0.170) v'

7.055 = (70) V' + (0.170) v'

V' = 0.1008 - 0.00243 v' eq-1

Using conservation of kinetic energy

(0.5) M V² + (0.5) m v² = (0.5) M V'² + (0.5) m v'²

M V² + m v² = M V'² + m v'²

(70) (0)² + (0.170) (41.5)² = (70) V'² + (0.170) v'²

292.8 = (70) V'² + (0.170) v'²

Using eq-1

292.8 = (70) (0.1008 + 0.00243 v')² + (0.170) v'²

v' = - 41.3 m/s

Using eq-1

V' = 0.1008 - 0.00243 v'

V' = 0.1008 - 0.00243 (- 41.3)

V' = 0.2012 m/s

6 0

4 years ago

What is static electricity

navik [9.2K]

Static electricity is electricity produced locally that does not flow. It is produced by electrons being rubbed off one object and collecting on another. It cannot flow through a wire like the electricity in your home.

Example:

1) Rub a balloon on your hair and it will stick to the wall. The balloon rubs electrons off your hair and picks up a negative charge. Your hair, in turn, is left with a positive charge. You may even notice your hair has "static" and is standing out from your head.

2) Comb your hair with a plastic comb then use it to pick up small pieces of paper. The comb picks up electrons from your hair and becomes negatively charged. It uses this charge to attract the pieces of paper.

3) Rub your slippered feet on the carpet and then touch something metal like a door knob. The "shock" you feel is static electricity. You pick up electrons from the carpet and discharge them on to the door knob.

3 0

3 years ago

Read 2 more answers

B. the hockey player is moving at a speed of 9. 5 m/s. if it takes him 2 seconds to come to a stop under constant acceleration,

balu736 [363]

The hockey player is moving at a speed of 9. 5 m/s. if it takes him 2 seconds to come to a stop under constant acceleration, will be s = 9.5 m.

The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Kinematics equations are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.

These equations link five kinematic variables:

Displacement (denoted by Δx)

Initial Velocity v0

Final Velocity denoted by v

Time interval (denoted by t)

Constant acceleration (denoted by a)

These equations define motion at either constant velocity or at constant acceleration. Because kinematics equations are only applicable at a constant acceleration or a constant speed, we cannot use them if either of the two is changing.

v = u + at

0 = 9.5 + a (2)

a = - 9.5 /2 m/ $s^{2}$

$v^{2}$ = $u^{2}$ + 2as

0 = $(9.5)^{2}$ + 2* (- 9.5 /2) * s

- $(9.5)^{2}$ = - 9.5 s

s = 9.5 m

To learn more about kinematics here

brainly.com/question/27126557

#SPJ4

3 0

2 years ago

If the coefficient of kinetic friction between tires and dry pavement is 0.84, what is the shortest distance in which you can st

liberstina [14]

Answer:

The shortest distance in which you can stop the automobile by locking the brakes is 53.64 m

Explanation:

Given;

coefficient of kinetic friction, μ = 0.84

speed of the automobile, u = 29.0 m/s

To determine the the shortest distance in which you can stop an automobile by locking the brakes, we apply the following equation;

v² = u² + 2ax

where;

v is the final velocity

u is the initial velocity

a is the acceleration

x is the shortest distance

First we determine a;

From Newton's second law of motion

∑F = ma

F is the kinetic friction that opposes the motion of the car

-Fk = ma

but, -Fk = -μN

-μN = ma

-μmg = ma

-μg = a

- 0.8 x 9.8 = a

-7.84 m/s² = a

Now, substitute in the value of a in the equation above

v² = u² + 2ax

when the automobile stops, the final velocity, v = 0

0 = 29² + 2(-7.84)x

0 = 841 - 15.68x

15.68x = 841

x = 841 / 15.68

x = 53.64 m

Thus, the shortest distance in which you can stop the automobile by locking the brakes is 53.64 m

4 0

3 years ago