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Daniel [21]
3 years ago
5

A calorimeter contained 350.0 g of water [cp=4.18 J/(g °C)] at 24.0 °C. An electric current was passed through a heater placed i

n the water. The heater transferred 16,700 J of energy to the water. What is the final temperature of the water?
Physics
1 answer:
Shtirlitz [24]3 years ago
4 0
Cp shows the amount of energy needed to raise temperature by one degree for one gram of water. 

Formula for calculating cp is:
cp= \frac{energy}{(mass)*( temperature_{change} ))}  \\ temperature_{change}= \frac{energy}{(mass)*( cp))}   \\  \\ temperature_{change}= \frac{16700}{(350)*( 4.18))}  \\  \\ temperature_{change}=2.73 \\  \\ temperature_{final} =temperature_{initial}+temperature_{change} \\ temperature_{final}=24 + 2.73 \\ temperature_{final}=26.73

Final temperature is 26.73°C.
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C), stimuli adaption. 
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3 years ago
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When serving a tennis ball, a player hits the ball when its velocity is zero (at the highest point of a vertical toss). The racq
Sindrei [870]

Answer:

<h2> 0.041kg</h2>

Explanation:

Step one:

given data

initial velocity u= 0m/s

Force F= 443N

time t= 4.3 ms= 0.0043seconds

final velocity v= 45.7m/s

Step two:

Required

mass m

we know that the expression for impulse is given as

Ft=mv

make m subject of the formula

m=Ft/v

substitute we have

m=443*0.0043/45.7

m=1.90/45.7

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The mass of the ball is 0.041kg

6 0
3 years ago
. Orbit of a satellite It is advantageous to place communications satellites in a circular orbit so that their position is fixed
Alexxx [7]

Answer:

a) r = 4.22 10⁷ m, b)  v = 3.07 10³ m / s  and c)  a = 0.224 m / s²

Explanation:

a) For this exercise we will use Newton's second law where acceleration is centripetal and force is gravitational force

     F = m a

     a = v² / r

     F = G m M / r²

    G m M / r² = m v² / r

    G M / r = v²

The squared velocity is a scalar and this value is constant, so let's use the uniform motion relationships

     v = d / t

As the orbit is circular the distance is the length of the circle in 24 h time

     d = 2π r

     t = 24 h (3600 s / 1 h) = 86400 s

Let's replace

     G M / r = (2π r / t)²

     G M = 4 π² r³ / t²

     r = ∛(G M t² / (4π²)

     r = ∛( 6.67 10⁻¹¹ 5.98 10²⁴ 86400² / (4π²)) = ∛( 75.4 10²¹)

     r = 4.22 10⁷ m

b) the speed module is

    v = √G M / r

    v = √(6.67 10⁻¹¹ 5.98 10²⁴/ 4.22 10⁷

    v = 3.07 10³ m / s

c) the acceleration is

    a = G M / r²

    a = 6.67 10⁻¹¹ 5.98 10²⁴ / (4.22 10⁷)²

    a = 0.224 m / s²

5 0
3 years ago
PLEASE HELP (100)
morpeh [17]

Answer:

The work done will be W=55.27\: J

Explanation:

The work equation is given by:

W=F\cdot x

Where:

F is the force due to gravity (weight = mg)

x is the length of the ramp (3 m)

Now, the force acting here is the component of weight in the ramp direction, so it will be:

F_{x-direction}=mgsin(28)

Therefore, the work done will be:

W=mgsin(28)*3

W=4*9.81*sin(28)*3

W=55.27\: J

I hope it helps you!

3 0
3 years ago
How far is the sun away from earth
lisabon 2012 [21]

Answer:

The Sun is at an average distance of about 93,000,000 miles (150 million kilometers) away from Earth. It is so far away that light from the Sun, traveling at a speed of 186,000 miles (300,000 kilometers) per second, takes about 8 minutes to reach us.

Explanation:

8 0
3 years ago
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