Question

A calorimeter contained 350.0 g of water [cp=4.18 J/(g °C)] at 24.0 °C. An electric current was passed through a heater placed in the water. The heater transferred 16,700 J of energy to the water. What is the final temperature of the water?

Answer 1

Cp shows the amount of energy needed to raise temperature by one degree for one gram of water. 

Formula for calculating cp is:
$cp= \frac{energy}{(mass)*( temperature_{change} ))} \\ temperature_{change}= \frac{energy}{(mass)*( cp))} \\ \\ temperature_{change}= \frac{16700}{(350)*( 4.18))} \\ \\ temperature_{change}=2.73 \\ \\ temperature_{final} =temperature_{initial}+temperature_{change} \\ temperature_{final}=24 + 2.73 \\ temperature_{final}=26.73$

Final temperature is 26.73°C.