Molar mass
NH3 = 17 g/mol
N2 = 28 g/mol
4 NH3 + 6 NO = 5 N2 + 6 H2O
4 x 17 g NH3 ------------ 5 x 28 g N2
?? g NH3 --------------- 300 g N2
300 x 4 x 17 / 5 x 28 =
20400 / 140 => 145.71 g of NH3
<u>Answer:</u> The molality of solution is 4.013 m
<u>Explanation:</u>
Molality is defined as the amount of solute expressed in the number of moles present per kilogram of solvent. The units of molarity are mol/kg.
The formula used to calculate molarity:
.....(1)
Given values:
Given mass of = 20.0 g
Molar mass of = 62.3 g/mol
Mass of solvent = 80.0 g
Putting values in equation 1, we get:
Hence, the molality of solution is 4.013 m
Answer:
hope it helps cuz i did not really understand
Answer:
pOH = -log[OH-]
log x =a <=> 10ª = x
so, if pOH is 10.75, we need to aply the anti log of it to get the [OH-], where x is [OH-] and a is pOH
using the calc, we have
-log [OH-] = 10.75 <=>10^(-10.75) = [OH-]
[OH-]= 1.78 x 10^(-11)
Answer:
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Explanation: