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Vedmedyk [2.9K]
3 years ago
10

Which of the following lists elements from lowest to highest atomic number

Chemistry
1 answer:
vitfil [10]3 years ago
8 0
Lowest is Hydrogen highest is <span>Beryllium
-HOPE THIS HELPED </span>
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Damm [24]

Answer: the answer is 18

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3 years ago
The purpose of an indicator is to
Grace [21]

Chemical indicators are used to identify when a reaction has undergone a chemical change or if it has reached completion.

8 0
3 years ago
Read 2 more answers
Explain how you can determine the number of neutrons in the nucleus of an atom of any of the elements listed in the table.
daser333 [38]

Different explanations that lead to the same result


-You need to substract the number of protons from the mass number.

-Mass number - atomic number= number of protons

-Following this  equation:

CARBON

atomic number= 6

mass number= 12

mass number= protons + neutrons

12= 6 + x

x= 12-6

x= 6



6 0
3 years ago
A friend asks you to help them decide which crackers are healthier. Comparing approximately equal serving sizes of 1 cracker (ap
Readme [11.4K]

Answer:

The correct option is "Triscsuit"

Explanation:

In my opinion the correct option is tricsuit, because it has 0% saturated fat and TRANS fat, which is healthy fats since these fats are the worst for our body.

They also contain sodium but their levels are not high enough to trigger hypertension.

8 0
3 years ago
the solubility product Ag3PO4 is: Ksp = 2.8 x 10^-18. What is the solubility of Ag3PO4 in water, in moles per liter?
guapka [62]

Answer : The solubility of Ag_3PO_4 in water is, 1.8\times 10^{-5}mol/L

Explanation :

The solubility equilibrium reaction will be:

Ag_3PO_4\rightleftharpoons 3Ag^++PO_4^{3-}

Let the molar solubility be 's'.

The expression for solubility constant for this reaction will be,

K_{sp}=[Ag^{+}]^3[PO_4^{3-}]

K_{sp}=(3s)^3\times (s)

K_{sp}=27s^4

Given:

K_{sp} = 2.8\times 10^{-18}

Now put all the given values in the above expression, we get:

K_{sp}=27s^4

2.8\times 10^{-18}=27s^4

s=1.8\times 10^{-5}M=1.8\times 10^{-5}mol/L

Therefore, the solubility of Ag_3PO_4 in water is, 1.8\times 10^{-5}mol/L

3 0
3 years ago
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