Answer:
a)0.024
b)0.148
Explanation:
Let 's represent the set of deer ticks Carrying Lyme disease with L and the set of deer ticks carrying Human Granulocytic Ehrlichiosis with H
Given:
P(L) = 0.16
P(H) = 0.10
P(L n H) = 0.1 ·P( L u H )
Hence, P( L u H) = 10 ·P( L nH)
(a)
Hence. using the equation. P(L U H) = P(L) + P(H) - P(L n H)
Hence, 10 · P(L n H ) = 0.16 + 0.1 - P(L n H )
Hence, 11 · P(L n H) = 0.16 + 0.1 = 0.26
Hence, P(L n H) =
0.26/11=0.024
(b)
We know that condition probability P(H ║ L) = p(L n H)/P(L)
hence, P(H ║ L) =(0.26/11)/0.16 =0.148
The velocity of pluck 1 is 12 m/s west.
<h3>What is the conservation of momentum?</h3>
The principle of the conservation of the linear momentum states that momentum before collision is equal to momentum after collision.
Now given that;
m1u1 + m2u2 = m1v1 + m2v2
(0.1 * 15) - (0.1 * 12) = 0.1* v + (0.1 * 15)
1.5 - 1.2 = 0.1v + 1.5
0.3 - 1.5 = 0.1v
v = -1.2/0.1
v = - 12 m/s
Hence, the velocity of pluck 1 is 12 m/s west.
Learn more about linear momentum:brainly.com/question/27988315
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