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Pachacha [2.7K]
3 years ago
5

3- (a) What is the period of rotation of Earth in seconds? (b) What is the angular velocity of Earth? (c) Given that Earth has a

radius of 40,075 km at its equator, what is the linear velocity at Earth’s surface?
Physics
1 answer:
ASHA 777 [7]3 years ago
7 0

Explanation:

a) The Earth makes 1 rotation in 24 hours.  In seconds:

24 hr × (3600 s / hr) = 86400 s

b) 1 rotation is 2π radians.  So the angular velocity is:

2π rad / 86400 s = 7.27×10⁻⁵ rad/s

c) The earth's linear velocity is the angular velocity times the radius:

40075 km × 7.27×10⁻⁵ rad/s = 2.91 km/s

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EleoNora [17]

Answer:

tex]\lambda_{Be}[/tex] = 22.78 nm

Explanation:

Bohr's model for the hydrogen atom has been used by other atoms with a single electric charge by changing the number of charges by the charge of the new atom (atomic number)

      E_{n}= k e² / 2a₀ (1 /n²)

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For another atom with a single electron in the last layer

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      E_{n} = - Z²  Eo/n²

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The transition occurs when the electron stops from one level to another

         E_{n} -  E_{m} = Z² E₀ (1 / n² - 1 / m²) = Z² ΔE

Let's relate this expression to the wavelength

       c = λ f

      E = h f

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Let's apply this last equation to our case

Lithium Z = 3

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Beryllium Z = 4

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Let's write our two equations is and solve

     40.5 10-9 = 1/9 λ_hydrogen

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      40.5 10⁻⁹ = 1/9 (16 \lambda_{Be} )

    tex]\lambda_{Be}[/tex] = 40.5 9/16

  tex]\lambda_{Be}[/tex] = 22.78 nm

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3 years ago
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