AD I=V/R
CURRENT =200/2 = 100AMPERE
Answer:
weight
Explanation:
The weight of an object is the force of gravity on the object and may be defined as the mass times the acceleration of gravity, w = mg. Since the weight is a force, its SI unit is the newton. Density is mass/volume.
Answer:
f λ = c = 3.00E8 frequency * wavelength = speed of light
λ = c / f = 3.00E8 / 4.0E14 = 7.5E-7 m
Note 1 angstrom = 1.00E-10 m and 1 milli-micron = 1.00E-9 m
So the wavelength would be 7500 angstroms
The visible spectrum is 4000 A - 7000 A or 400 - 700 milli-microns
Complete question:
A uniform electric field is created by two parallel plates separated by a
distance of 0.04 m. What is the magnitude of the electric field established
between the plates if the potential of the first plate is +40V and the second
one is -40V?
Answer:
The magnitude of the electric field established between the plates is 2,000 V/m
Explanation:
Given;
distance between two parallel plates, d = 0.04 m
potential between first and second plate, = +40V and -40V respectively
The magnitude of the electric field established between the plates is calculated as;
E = ΔV / d
where;
ΔV is change in potential between two parallel plates;
d is the distance between the plates
ΔV = V₁ -V₂
ΔV = 40 - (-40)
ΔV = 40 + 40
ΔV = 80 V
E = ΔV / d
E = 80 / 0.04
E = 2,000 V/m
Therefore, the magnitude of the electric field established between the plates is 2,000 V/m
Answer:
she is going to be mad dude
