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3 years ago

HELP ME.. I NEED TO HAND IT IN NOW!

Chemistry

2 answers:

larisa86 [58]3 years ago

5 0

You answered it right

anygoal [31]3 years ago

4 0

Answer:it always desolve in the water

Explanation:because is a

Table salt dissolves in water because the very polar water molecules attract both the positively charged sodium ions and the negatively charged chloride ions. This interaction is called an ion / dipole interaction.

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What is the pH of a 1.0 x 10-2 M HNO3 solution?

umka21 [38]

PH=-log(1.0x10-2)
=2.
Double-check my math tho

5 0

3 years ago

A Cu2+ solution is prepared by dissolving a 0.4749 g piece of copper wire in acid. The solution is then passed through a Walden

Luda [366]

Answer:

Concentration of $Cr_2O_7^{2-}$ = 0.03101 M

Concentration of $MnO_4^-$ = 0.03721 M

Explanation:

The reduction for $Cr_2O_7^{2-}$ is;

$Cr_2O_7^{2-} + 14 H ^+ _{(aq)} + 6 e^- -----> 2 Cr^{3+} _{(aq)}+7H_2O _{(l)}$

$Cu^+_{(aq)} -----> Cu^{2+} _{(aq)} + 1 e^-$

6 moles of $Cu ^+$ = 1 mole of $Cr_2O_7^{2-}$

number of moles of Cu reacted = $\frac{mass \ of \ Cu \ wire }{ molecular weigh tof \ Cu wire }$

number of moles of Cu reacted = $\frac{0.4749}{63.55}$

number of moles of Cu reacted = 0.00747 mole

number of moles of $Cr_2O_7^{2-}$ reacted = $\frac{0.00747}{6}$

number of moles of $Cr_2O_7^{2-}$ reacted = 0.001245 mole

Concentration of $Cr_2O_7^{2-}$ = $\frac{number \ of moles }{Volume}$

Given that the volume = 40.15 mL = $40.15 *10^{-3}$ ; we have:

Concentration of $Cr_2O_7^{2-}$ = $\frac{0.001245}{40.15*10^{-3}}$

Concentration of $Cr_2O_7^{2-}$ = 0.03101 M

The reduction for $MnO_4^-$ is;

$MnO_4^- + 8H^+ + 5 e^- -----> Mn^{2+} + 4H_2O$

$Cu^+_{(aq)} -----> Cu^{2+} _{(aq)} + 1 e^-$

5 moles of $Cu ^+$ = 1 mole of $Cr_2O_7^{2-}$

number of moles of Cu reacted = $\frac{mass \ of \ Cu \ wire }{ molecular weigh tof \ Cu wire }$

number of moles of Cu reacted = $\frac{0.4749}{63.55}$

number of moles of Cu reacted = 0.00747 mole

number of moles of $MnO_4^-$ reacted = $\frac{0.00747}{5}$

number of moles of $MnO_4^-$ reacted = 0.001494 mole

Concentration of $MnO_4^-$ = $\frac{number \ of moles }{Volume}$

Given that the volume = 40.15 mL = $40.15 *10^{-3}$ ; we have:

Concentration of $MnO_4^-$ = $\frac{0.001494 }{40.15*10^{-3}}$

Concentration of $MnO_4^-$ = 0.03721 M

3 0

4 years ago

Use your knowledge of atoms, bonding, and the periodic table to complete the chemical equation .”CH4 + O2

kherson [118]

Answer:

CH4 + O2 = CO2 + H2O.

3 0

3 years ago

Read 2 more answers

When a gas is dissolved in a liquid, what happens when the pressure increases?<br>

erik [133]

Answer: B, the gas is being squeezed out of the liquid.

Explanation: The gas does not want to be trapped inside of the liquid, so it is trying to force it’s way out. Therefore creating more pressure in the container or whatever the liquid is being held in.

8 0

3 years ago

Identify the acid, base, conjugate acid, and conjugate base in the following reaction:

myrzilka [38]

Answer:

Acid: HSO4-

Base: NH3

Conjugate Acid: NH4+

Conjugate Base: SO4-2

Explanation:

HSO4- gives a H+ to NH3 making NH4+ the conjugate acid.

Same can be said to the base.

3 0

2 years ago

HELP ME.. I NEED TO HAND IT IN NOW! ​

HELP ME.. I NEED TO HAND IT IN NOW!