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Dvinal [7]
3 years ago
5

How many moles of sulfur trioxide are formed from 3 moles of oxygen using the given

Chemistry
1 answer:
fiasKO [112]3 years ago
8 0

Answer:

6 moles of SO₃ formed.

Explanation:

Given data:

Number of moles of SO₃ formed = ?

Number of moles of oxygen react = 3 mol

Solution:

Chemical equation;

2SO₂+ O₂      →   2SO₃

now we will compare the moles of oxygen and sulfur trioxide.

                             O₂            :            SO₃

                               1             :             2

                               3            :           2/1×3 = 6 moles

Thus, six moles of SO₃ will formed.

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In a reaction A+B--->C, reactant A has 5g of product C has 9g of product. How many grams should reactant B contain?
Rzqust [24]

According to the law of conservation of Mass:

In a chemical reaction mass can neither be created nor be destroyed

So, we can say that: Mass of A + Mass of B = Mass of C

In the given reaction,

One of the reactants weigh 5 grams and another one weighs x grams

The mass of the product of this reaction is 9 grams

<u>Mass of reactant B:</u>

Mass of A + Mass of B = Mass of C

5 + x = 9

x = 4 grams

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3 years ago
Why are gold and platinum sutible for making jewellery ? ​
Anon25 [30]

Answer:

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Explanation:

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2 years ago
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A chemist has synthesized two new dyes based on the molecular structure of plant-based dyes. The lowest energy absorption line f
Nimfa-mama [501]

Answer:

1. The dye that absorbs at 530 nm.

Explanation:

The dye will absorb light to promote the transition of an electron from the HOMO to the LUMO orbital.

The higher the gap, the higher the energy of transition. The energy can be calculated by E = hc/λ, in which h and c are constants and λ is the wavelength.

The equation shows that the higher the energy, the higher the gap and the lower the wavelength.

Therefore, the dye with absorption at 530 nm has the higher HOMO-LUMO gap.

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PLEASE ANSWER: The density of a gas at STP is 0.75 g/L. What is the mass of this gas?
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3 0
3 years ago
A stock solution of sodium sulfate NaSO4 has a concentrate of 1.00 m. The volume of this solution is 50 ml. What volume of 0.25
mylen [45]
<h3>Answer:</h3>

200 mL

<h3>Explanation:</h3>

Concept tested: Dilution formula

We are given;

  • Concentration of stock solution as 1.00 M
  • Volume of the stock solution as 50 mL
  • Molarity of the dilute solution as 0.25 M

We are required to calculate the volume of diluted solution;

  • The stock solution is the original solution before dilution while diluted solution is the solution after dilution.
  • Using the dilution formula we can determine the volume of diluted solution;

M1V1 = M2V2

Rearranging the formula;

V2 = M1V1 ÷ M2

     = (1.00 M × 50 mL) ÷ 0.25 M

     = 200 mL

Therefore, a volume of 200mL of 0.25 M solution could be made from the stock solution.

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3 years ago
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