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3 years ago

A sample of lithium sulfate, (Li2SO4), has 2.94 x 1023 atoms

Chemistry

1 answer:

Crazy boy [7]3 years ago

3 0

Answer:

0.245 moles

Explanation:

moles of lithium = 2*moles of Li2SO4

so moles of LI2SO4=2.94*10^23/(2*6*10^23)=0.245

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PLSSS HELP I AM STUCK ON THIS PROBLEM!!!

DENIUS [597]

Answer:

i can't read it.. maybe upload a visible picture?

6 0

3 years ago

CH3CH2PH2 can be synthesized by an SN2 reaction. Draw the structures of the alkyl chloride and nucleophile that will give this c

Maru [420]

Answer:

The PH2 becomes attached to the alkyl halide with inversion of configuration

Explanation:

SN2 reaction involves the simultaneous attachment of the nucleophile as the leaving group departs. This leads to an inversion of configuration because the sterochemistry around the carbon bearing the leaving group is reversed. The reaction proceed via a crowded five coordinate transition state. Details are shown in the image attached.

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3 years ago

A compound has the following percentages by mass: barium, 58.8%; sulfur, 13.74%; oxygen, 27.43%. Determine the empirical formula

lys-0071 [83]

Answer:

BaSO₄

Explanation:

Let's assume we have 100 g of the compound. If that's the case we would have:

58.8 g of Ba

13.74 g of S

27.43 g of O

Now we convert the masses of each element into moles, using their respective molar masses:

58.8 g Ba ÷ 137.327 g/mol = 0.428 mol Ba

13.74 g S ÷ 32 g/mol = 0.429 mol S

27.43 g O ÷ 16 g/mol = 1.71 mol O

We divide those moles by the lowest number among them:

0.428 mol Ba / 0.428 = 1

0.429 mol S / 0.428 ≈ 1

1.71 mol O / 0.428 = 4

We can express those results as Ba₁S₁O₄, meaning the empirical formula is thus BaSO₄.

5 0

3 years ago

How many grams of calcium chloride will be produced when 29.0 g of calcium carbonate is combined with 15.0 g of hydrochloric aci

horsena [70]

Answer:

22.7 g of CaCl₂ are produced in the reaction

Explanation:

This is the reaction:

CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O

Now, let's determine the limiting reactant.

Let's divide the mass between the molar mass, to find out moles of each reactant.

29 g / 100.08 g/m = 0.289 of carbonate

15 g / 36.45 g/m = 0.411 of acid

1 mol of carbonate must react with 2 moles of acid

0.289 moles of carbonate will react with the double of moles (0.578)

I only have 0.411 of HCl, so the acid is the limiting reactant.

Ratio is 2:1, so I will produce the half of moles, of salt.

0.411 / 2 = 0.205 moles of CaCl₂

Mol . molar mass = mass → 0.205 m . 110.98 g/m = 22.7 g

5 0

4 years ago

Which of the following reactions shows that the formation of CO2 releases

tiny-mole [99]

Answer:

A. C(s) + O2(g) → CO2(g) + 393.5 kJ

Explanation:

The formation of carbon IV oxide (CO2) is an exothermic process. n exothermic process is a chemical process in which heat is evolved. Speaking in lay man's terminology, heat is one of the 'products' of the reaction. This implies that heat is evolved by the process.

The formation of CO2 is always a combustion reaction where heat is evolved or released by the reaction system. Hence the reaction could be shown as;

C(s) + O2(g) → CO2(g) + 393.5 kJ

This implies that 393.5 kJ of energy is released in the reaction in the form of heat. Hence the answer given in the answer box.

7 0

3 years ago