1. M(x)=12x, with domain x < or =30, x a natural number {1,2,3,...30}
2. T(y)=12*30+15y
T(y)=360+15y is the function which gives the wage after 30 hours of regular time and y of overtime.
3. T(y)=510
360+15y=510
15y=510-360=150
y=10 hours of overtime (and 30 of regular time.
Put the numbers in order.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 2: Find the median.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 3: Place parentheses around the numbers above and below the median.
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
(1, 2, 5, 6, 7), 9, (12, 15, 18, 19, 27).
Step 4: Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
(1, 2, 5, 6, 7), 9, ( 12, 15, 18, 19, 27). Q1 = 5 and Q3 = 18.
Step 5: Subtract Q1 from Q3 to find the interquartile range.
18 – 5 = 13.
Six Squares, the answer is 36.
Answer:
D
Step-by-step explanation:
if cosec is 13/5 then sin is 5/13
The inverse of
is
. (This eliminates B and D)
translates to "if
, then
". This means the answer must be A.
