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hjlf
3 years ago
7

HELP PLEASE NEED IT TO BE RIGHT

Physics
2 answers:
vivado [14]3 years ago
7 0

Answer: Solvent

Explanation: a solvent is a substance that disolves a solute

hope this helps !

Grace [21]3 years ago
4 0

Answer:

It's solute I just took the test and solvent is wrong

Explanation:

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Two planets A and B, where B has twice the mass of A, orbit the Sun in elliptical orbits. The semi-major axis of the elliptical
lozanna [386]

Answer:

2.83

Explanation:

Kepler's discovered that the square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit, that is called Kepler's third law of planet motion and can be expressed as:

T=\frac{2\pi a^{\frac{3}{2}}}{\sqrt{GM}} (1)

with T the orbital period, M the mass of the sun, G the Cavendish constant and a the semi major axis of the elliptical orbit of the planet. By (1) we can see that orbital period is independent of the mass of the planet and depends of the semi major axis, rearranging (1):

\frac{T}{a^{\frac{3}{2}}}=\frac{2\pi}{\sqrt{GM}}

\frac{T^{2}}{a^{3}}=(\frac{2\pi }{\sqrt{GM}})^2 (2)

Because in the right side of the equation (2) we have only constant quantities, that implies the ratio \frac{T^{2}}{a^{3}} is constant for all the planets orbiting the same sun, so we can said that:

\frac{T_{A}^{2}}{a_{A}^{3}}=\frac{T_{B}^{2}}{a_{B}^{3}}

\frac{T_{B}^{2}}{T_{A}^{2}}=\frac{a_{B}^{3}}{a_{A}^{3}}

\frac{T_{B}}{T_{A}}=\sqrt{\frac{a_{B}^{3}}{a_{A}^{3}}}=\sqrt{\frac{(2a_{A})^{3}}{a_{A}^{3}}}

\frac{T_{B}}{T_{A}}=\sqrt{\frac{2^3}{1}}=2.83

6 0
3 years ago
Read 2 more answers
A proton is released from rest at the origin in a uniform electric field in the positive x direction with magnitude 850 N/C. Wha
Gwar [14]

A proton is released from rest at the origin in a uniform electric field in the positive x direction with magnitude 850 N/C. The change in the electric potential energy of the proton-field system when the proton travels to x = 2.50m is -3.40 × 10⁻¹⁶ J (Option B)

<h3 /><h3>How is the change in electric potential energy of the proton-field system calculated?</h3>

  • Work done on the proton =Negative of the change in the electric potential energy of the proton field
  • In the given case, W = -qΔV
  • -W = qΔV
  • = qEcosθ
  • Therefore, work done on the proton = -e(8.50×10^2 N/C)(2.5m)(1)
  • = -3.40×10^-^1^6 J
  • Any change in the potential energy indicates the work done by the proton.
  • Therefore the positive sign shows that the potential energy increases when the proton does the work.
  • The negative sign shows that the potential energy decreases when the proton does the work.

To learn more about electric potential energy, refer

brainly.com/question/14306881

#SPJ4

3 0
1 year ago
Hii so I am out of town unable to do this for my class can you guys use things in your own home? I will BRAINLIST!!1
ExtremeBDS [4]
1.)t.v
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7 0
2 years ago
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The magnitude of the Poynting vector of a planar electromagnetic wave has an average value of 0.939 W/m2. The wave is incident u
Hatshy [7]

Answer:

The  total energy is  T  =  169.02 \ J

Explanation:

From the question we are told that

    The  Poynting vector (energy flux ) is  k  =  0.939 \ W/m^2

    The length of the rectangle is  l  =  1.5  \ m

    The  width of the rectangle is  w =  2.0 \ m

    The time taken is t  =   1 \ minute  =  60 \ s

The total electromagnetic energy falls on the area is mathematically represented as

      T  =  k  *  A  *  t

Where A  is the area of the rectangle which is mathematically represented as

           A= l *  w

 substituting values

         A= 2 * 1.5

        A=  3 \ m^2

substituting values

        T  =  0.939 *  3 *  60

        T  =  169.02 \ J

5 0
3 years ago
Write about any five form of energy with example​
Andrei [34K]

Answer:

The different types of energy include thermal energy, radiant energy, chemical energy, nuclear energy, electrical energy, motion energy, sound energy, elastic energy and gravitational energy.

6 0
3 years ago
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