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hram777 [196]
4 years ago
10

Need help, thank you! 2x+3y=5x−y y=0 x=?

Mathematics
1 answer:
jonny [76]4 years ago
3 0

Answer:

x is also 0

Step-by-step explanation:

If we substitute y as 0, we get

2x=5x\\5x-2x=0\\3x=0\\x=0

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57.036 in word form and in expanded form.
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Finding an Equation of a Tangent Line In Exercise, find an equation of the tangent line to the graph of the function at the give
Inga [223]

Answer:

y = 1/e

y = 0.37

Step-by-step explanation:

y = (ln x)/x; (e, 1/e)

Step 1

Find the point of tangency.

It's given as (e,1/e) or (2.72,0.37)

Step 2

Find the first derivative, and evaluate it at x=e

Using product rule.

d(uv) = udv + vdu

Where u = lnx and v = 1/x

du = 1/x , dv = -1/x^2

f'(x) = -lnx/x^2 +1/x^2

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At x = e

f'(e) = (1-lne)/e^2

f'(e) = 0

The slope of the tangent line at this point is m= 0

Step 3

Find the equation of the tangent line at (e,1/e) with a slope of m=0

y−y1 = m(x - x1)

y-(1/e) = 0(x-1)

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6 0
3 years ago
Please help, will give brainliest!!
bogdanovich [222]

Answer:

15°

Step-by-step explanation:

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b

20 ×n=360

n=360/20=18

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c.

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4 years ago
TIMED TEST
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Answer:

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Step-by-step explanation:

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3 years ago
Read 2 more answers
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