Structure of a-chloro-b-methylbutyric acid (2-chloro-3-methylbutyric acid is attached below.
The structure was drawn using following information.
1) First, the parent chain was identified. The parent chain is containing four carbon atoms, also, this chain belongs to carboxylic acid as the compound name ends with Butyric acid i.e. butyr (Butane) -ic acid (carboxylic acid).
2) Secondly, the positions of substituents were assigned by using the rule which sates that the numbering in carboxylic acid must satrt from the carbonyl carbon. Therefore, the carbon which is attached to carbonyl carbon is named as alpha (2nd position) and carbon next to alpha carbon is named as beta carbon (3rd position). Hence, we add chlorine atom on 2nd carbon next to carbonyl group and methyl group at 3rd carbon with respect to carbonyl carbon.
Answer:
C, longitudinal waves
Explanation:
A sound wave traveling through air is a longitudinal wave
Answer:
Yes it is
Explanation: because it is composed of identical molecules consisting of atoms of two or more chemical elements.
hope it helps <3
Answer:
Follows are the solution:
Explanation:
A + B = C
Its response decreases over time as well as consumption of a reactants.
r = -kAB
during response A convert into 2x while B convert into x to form 3x of C
let's y = C
y = 3x
Still not converted sum of reaction
for A: 100 - 2x
for B: 50 - x
Shift of x over time
Integration of x as regards t
![\frac{1}{[(100 - 2x)(50 - x)]} dx = -k dt\\\\\frac{1}{2[(50 - x)(50 - x)]} dx = -k dt\\\\\ integral\ \frac{1}{2[(50 - x)^2]} dx =\ integral [-k ] \ dt\\\\\frac{-1}{[100-2x]} = -kt + D \\\\](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5B%28100%20-%202x%29%2850%20-%20x%29%5D%7D%20dx%20%3D%20-k%20dt%5C%5C%5C%5C%5Cfrac%7B1%7D%7B2%5B%2850%20-%20x%29%2850%20-%20x%29%5D%7D%20dx%20%3D%20-k%20dt%5C%5C%5C%5C%5C%20integral%5C%20%20%5Cfrac%7B1%7D%7B2%5B%2850%20-%20x%29%5E2%5D%7D%20dx%20%3D%5C%20integral%20%5B-k%20%5D%20%5C%20dt%5C%5C%5C%5C%5Cfrac%7B-1%7D%7B%5B100-2x%5D%7D%20%3D%20-kt%20%2B%20D%20%5C%5C%5C%5C)
D is the constant of integration
initial conditions: t = 0, x = 0
![\frac{-1}{[100-2x]} = -kt + D \\\\\frac{ -1}{[100]} = 0 + D\\\\D= \frac{-1}{100}\\\\](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B%5B100-2x%5D%7D%20%3D%20-kt%20%2B%20D%20%20%20%5C%5C%5C%5C%5Cfrac%7B%20-1%7D%7B%5B100%5D%7D%20%3D%200%20%2B%20D%5C%5C%5C%5CD%3D%20%5Cfrac%7B-1%7D%7B100%7D%5C%5C%5C%5C)
hence we get:
![\frac{-1}{[100-2x]}= -kt -\frac{1}{100}\\\\or \\\\ \frac{1}{(100-2x)} = kt + \frac{1}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B%5B100-2x%5D%7D%3D%20-kt%20-%5Cfrac%7B1%7D%7B100%7D%5C%5C%5C%5Cor%20%5C%5C%5C%5C%20%5Cfrac%7B1%7D%7B%28100-2x%29%7D%20%3D%20kt%20%2B%20%5Cfrac%7B1%7D%7B100%7D)
after t = 7 minutes , 
Insert the above value x into 
equation 
to get k.
therefore plugging in the equation the above value of k
Let y = C
, calculate C:
y = 3x
amount of C formed in 28 mins
plug t = 28
therefore amount of C formed in 28 minutes is = 3x = 144.78 grams
C:
y= 136.5 =137
