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MrRissso [65]
4 years ago
6

Object a has a mass of 12 grams and a density of 3 grams centimeters cubed object B has a mass of 12 grams and a density of 5 gr

am which object has a greater volume and by how much? A. Object a, by 2 6 cubic centimeters. B. Object A by 1.6 cubic centimeters C.object B by 2 6 cubic centimeters D object B by 1.6 cubic centimeters
Chemistry
1 answer:
gregori [183]4 years ago
8 0
Your answer is going to be A
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The vertical columns on the periodic table are called groups, how many groups are there on the periodic table?
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8 groups, 1 to 7 and most people call group 8 group 0 because the noble gases in group 0 have the outer electron shell full, so for example argon has 18 electrons, so it’s structure is 2.8.8 with its outer shell full. Also the number of the last shell defies what group it’s in, for example sodium is in group 1 so it’s structure is 2.8.1. Hope this helps.
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Which best describes the motion of molecules in the gaseous state?
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3 years ago
Read the false statement. Atoms of elements with one valence electron form anions in order to meet the octet rule. Which answer
Zepler [3.9K]

Answer:

C. Atoms of elements with five to seven valence electrons form anions in order to meet the octet rule.

Explanation:

  • Atoms of elements gain or lose electron(s) to obey the octet rule by forming cations or anions.
  • Atoms with 1 to 3 valence electrons lose electrons to form cations in order to attain a stable configuration.
  • Atoms with 5 to 7 valence electrons gain electron(s) to form anions in order to attain stable configuration.
  • However, atoms with 8 valence electrons do not require to gain or lose electrons since they an octet configuration.
  • Atoms of metallic elements such as those in group 1 and 2 lose electron(s) to form cations while atoms of non-metallic elements such as halogens require to gain electron(s) to form anions so as to obey the octet rule.
7 0
4 years ago
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Calculate the number of hydrogen atoms in a sample of hydrazine . Be sure your answer has a unit symbol if necessary, and round
gladu [14]

Answer:

atoms \ H= 9.767x10^{24}atoms

Explanation:

Hello!

In this case, considering that the mass of hydrazine is missing, we can assume it is 130.0 g (a problem found on ethernet). In such a way, since we need a mass-mole-atoms relationship by which we can compute moles of hydrazine given its molar mass (32.06 g/mol), then the moles of hydrogen considering one mole of hydrazine has four moles of hydrogen and one mole of hydrogen has 6.022x10²³ atoms (Avogadro's number); therefore, we proceed as shown below:

atoms \ H=130.0gN_2H_4*\frac{1molN_2H_4}{32.06gN_2H_4} *\frac{4molH}{1molN_2H_4} *\frac{6.022x10^{23}atoms}{1molH}\\\\atoms \ H= 9.767x10^{24}atoms

Notice 130.0 g has four significant figures, therefore the result is displayed with four as well.

Best regards!

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