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3 years ago

12

(x-3) (x2+2x+1) Foil method

1 answer:

AveGali [126]3 years ago

8 0

Step-by-step explanation:

(x-3)(x^2+2x+1)

=x^3-3x^2+2x^2-6x+x-3

=x^3+2x^2-3x^2-6x+x-3

=x^3-x^2-5x-3

___________

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91. If there is no real number solution to the quadratic equation, x^2+2x+C=0, what is a possible value of c?

malfutka [58]

For no real solution, you must have b^2 - 4ac of the quadratic formula be less than 0.

a = 1; b = 2; c = C

b^2 - 4ac < 0

2^2 - 4(1)(C) < 0

4 - 4C < 0

-4C < -4

C > 1

The only choice greater than 1 is 3.

Answer: the 4th choice, 3

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3 years ago

Plz help <br><br>answer fast<br> irrelevant answers will be reported <br><br>

Diano4ka-milaya [45]

Answer:

$1+\sqrt{2}\\$ , $1.5-\sqrt{2}$ , $\sqrt{2} -1$ , $\sqrt{2}-1 , 0.15+\pi /1000 , \sqrt{2} +0.001$ $2.357+\pi /1000000$ $0.0001+\pi /10000000$ and I think you got it, just add to the smaller one $\pi /10000000000000\\$

Step-by-step explanation:

not much to explain, it ןs irrational because $\sqrt{2} and \pi$ arent rattional.

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3 years ago

What is the radius of the circle who’s equation is x^2 + y^2 = 9

Svetllana [295]

Answer:

r=3

Step-by-step explanation:

The equation of a circumference is $(x-a)^2+(y-b)^2=r^2$ .
Then , in this case $r^2=9$ , and then to know the value of r we just simply have to calculate the square root of 9, which is 3.

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4 years ago

If 5.5 ounces of silver is worth $80 how much could you buy with $15 (setup and solve a proportion)

Liono4ka [1.6K]

Answer:

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3 years ago

Find the exact values of the following,giving your answers as fractions

Vsevolod [243]

Answer:

(a) $3^{-2}=\frac{1}{9}$

(b) $4^{-3}=\frac{1}{64}$

(c) $2^{-6}=\frac{1}{64}$

Step-by-step explanation:

To find the exact value in fractions of the followings:

Exponents also called powers its a way of expressing a number multiplied by itself by a certain number of times.

Using $a^{-m}= \frac{1}{a^m}$ .......[1]

(a)

Fraction represents a part of a whole or more generally, any number of equal parts.

$3^{-2}$ = $\frac{1}{3^2}=\frac{1}{3\times 3}=\frac{1}{9}$ [ Using [1]]

(b)

$4^{-3}$ = $\frac{1}{4^3} =\frac{1}{4\times 4\times 4}=\frac{1}{64}$ [ Using [1]]

(c)

$2^{-6}$ = $\frac{1}{2^6} =\frac{1}{2\times 2\times 2\times 2\times 2\times 2}=\frac{1}{64}$ [ Using [1]]

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3 years ago