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Nataliya [291]
3 years ago
12

A copper plate is free to swing between the poles of a large electromagnet. When the field is turned up the plate Group of answe

r choices will swing faster. will not be affected at all. will brake and quickly come to rest. will swing with a larger amplitude, because it is pushed by the magnet. will become a permanent magnet.
Physics
1 answer:
lbvjy [14]3 years ago
4 0

Answer:

C: will brake and quickly come to rest.

Explanation:

Correct answer is option C because for the swinging motion of the copper plates between the magnetic field which is set up as a result of it being between the two magnetic poles, there will be a continuous change of magnetic field flux that will be linked with the swinging pendulum.

As a result of this continuous change of magnetic field flux, it makes eddy currents to be set up in the copper plate which according to the Lenz's laws of electromagnetic induction tries to oppose the motion of the swinging pendulum and finally will make it come to rest.

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3 years ago
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A cart is moving to the right with a constant speed of 20 m s . A box of mass 80 kg moves with the cart without slipping. The co
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Answer:

Explanation:

Given

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f_r=ma

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4 0
3 years ago
Becky has a younger sister. If the sister was half Becky's age when Becky was 6, and Becky is now 70, how old is Becky's sister?
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Explanation:

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A scientist spends most of her time observing the motion of objects and how they behave. Which branch of science is she most lik
olga55 [171]
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7 0
2 years ago
A 2200-kg railway freight car coasts at 4.1 m/s underneath a grain terminal, which dumps grain directly down into the freight ca
777dan777 [17]

Answer:

The answer is "2.41 \times 10^3"

Explanation:

Given:  

m_i = 2000 \ kg \\\\v_i= 4.1 \ \frac{m}{s} \\\\v_f = 3.4 \ \frac{m}{s} \\

Using formula:  

\to m_iv_i = m_fv_f \\\\\to m_f= \frac{m_iv_i}{v_f}

p_i, p_f = system initial and final linear momentum.

V_i, v_f = system original and final linear pace.

m_i = original weight of the car freight.

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= \frac{ 2000 \times 4.1}{3.4}\\\\= \frac{ 8.2\times 10^3}{3.4}\\\\= 2.41 \times 10^3

\boxed{m_f = 2.41 \times 10^3}

8 0
2 years ago
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