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Nataliya [291]
3 years ago
12

A copper plate is free to swing between the poles of a large electromagnet. When the field is turned up the plate Group of answe

r choices will swing faster. will not be affected at all. will brake and quickly come to rest. will swing with a larger amplitude, because it is pushed by the magnet. will become a permanent magnet.
Physics
1 answer:
lbvjy [14]3 years ago
4 0

Answer:

C: will brake and quickly come to rest.

Explanation:

Correct answer is option C because for the swinging motion of the copper plates between the magnetic field which is set up as a result of it being between the two magnetic poles, there will be a continuous change of magnetic field flux that will be linked with the swinging pendulum.

As a result of this continuous change of magnetic field flux, it makes eddy currents to be set up in the copper plate which according to the Lenz's laws of electromagnetic induction tries to oppose the motion of the swinging pendulum and finally will make it come to rest.

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Sav [38]

Answer:

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Explanation:

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4 0
2 years ago
A 50kg boy runs at a speed of 10.0m/s and jumpsonto a cart
andriy [413]

Answer:

the mass of the cart is 150 kg

Explanation:

given,

mass of boy(m) = 50 kg

speed of boy (v)= 10 m/s                  

initial velocity of cart (u) = 0                    

final velocity of cart(V) = 2.5 m/s              

mass of the cart(M) = ?                              

m v + M u = (m + M ) V......................(1)

50× 10 + 0 = (50 + M ) 2.5

M =\dfrac{500}{2.5} - 50

M = 150 Kg                                          

hence, the mass of the cart is 150 kg

4 0
2 years ago
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drek231 [11]
Nice couch lol
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4 0
3 years ago
If anyone knows how to do any of these PLEASE help me....im am so confused rn and our teacher sucks at explaining this stuff....
Taya2010 [7]
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7 0
3 years ago
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A 1300 kg car starts at rest and rolls down a hill from a height of 10.0 m. It then moves across a
Makovka662 [10]

Answer:

0.51 m

Explanation:

Using the principle of conservation of energy, change in potential energy equals to the change in kinetic energy of the spring.

Kinetic energy, KE=½kx²

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Potential energy, PE=mgh

Where g is acceleration due to gravity, h is height and m is mass

Equating KE=PE

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Making x the subject of formula

x=\sqrt {\frac {2mgh}{k}}

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x=\sqrt \frac {2*1300*9.81*10}{1000000}=0.50503465227646m\\x\approx 0.51 m

5 0
3 years ago
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