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Nataliya [291]
3 years ago
12

A copper plate is free to swing between the poles of a large electromagnet. When the field is turned up the plate Group of answe

r choices will swing faster. will not be affected at all. will brake and quickly come to rest. will swing with a larger amplitude, because it is pushed by the magnet. will become a permanent magnet.
Physics
1 answer:
lbvjy [14]3 years ago
4 0

Answer:

C: will brake and quickly come to rest.

Explanation:

Correct answer is option C because for the swinging motion of the copper plates between the magnetic field which is set up as a result of it being between the two magnetic poles, there will be a continuous change of magnetic field flux that will be linked with the swinging pendulum.

As a result of this continuous change of magnetic field flux, it makes eddy currents to be set up in the copper plate which according to the Lenz's laws of electromagnetic induction tries to oppose the motion of the swinging pendulum and finally will make it come to rest.

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An electron moving parallel to a uniform electric field increases its speed from 2.0 × 10^7 m/s to 4.0 × 10^7 m/s over a distanc
julia-pushkina [17]

Answer:

E = 2.84 * 10^5 N/C

Explanation:

The speed increased from 2.0 * 10^7 m/s to 4.0 * 10^7 m/s over a 1.2 cm distance.

Let us find the acceleration:

v^2 = u^2 + 2as

(4.0 * 10^7)^2 = (2.0 * 10^7)^2 + 2 * a * 0.012\\\\(4.0 * 10^7)^2 - (2.0 * 10^7)^2 = 0.024a\\\\1.2 * 10^{15}= 0.024a\\\\a = 1.2 * 10^{15} / 0.024\\\\a = 5 * 10^{16} m/s^2

Electric force is given as the product of charge and electric field strength:

F = qE

where q = electric charge

E = Electric field strength

Force is generally given as:

F = ma

where m = mass

a = acceleration

Equating both:

ma = qE

E = ma / q

For an electron:

m = 9.11 × 10^{-31} kg

q = 1.602 × 10^{-19} C

Therefore, the electric field strength of the electron is:

E = \frac{9.11 * 10^{-31} * 5 * 10^{16}}{1.602 * 10^{-19}} \\\\E = 2.84 * 10^5 N/C

8 0
3 years ago
Which of the following is not a source of light? *<br> a) sun<br> b) star<br> c) mirror<br> d)cfl
Vladimir [108]

I think that would be c) mirror because mirrors reflects light and can't create it.

5 0
3 years ago
Physical properties of a base include...
neonofarm [45]

The correct answer is A

8 0
3 years ago
An unfortunate astronaut loses his grip during a spacewalk and finds himself floating away from the space station, carrying only
alexira [117]

Answer:

The answer is "2.352 \ \frac{m}{s}"

Explanation:

\to mass(m_1)=102 \ kg\\\\\to  mass(m_2)=10 \ kg \\\\\to v=2.10\ \frac{m}{s}\\\\

momentum before:

\to p=(m_1+m_2)v

       =(102+10)2.10\\\\=(102\times 2.10 +10 \times 2.10)\\\\=214.2+21\\\\=235.2

momentum After:

\to p=(m_1+m_2)v

       =(102\times 0 +10 \times v)\\\\ =(0 +10v)\\\\=10v\\

Calculating the conservation of momentum:

\to \text{momentum before = momentum After}

\to 235.2=10v\\\\\to v= \frac{235.2}{10}\\\\ \to v=2.352 \ \frac{m}{s}

3 0
3 years ago
Would you expect to find more impact craters on Io or Callisto? Why?
Doss [256]

Answer:

Callisto. As Io is geologically active body.

Explanation:

Io and Callisto are 2 of the Galilean moons of Jupiter. Io is most geologically active body in the solar system which means that a lot of volcanic activity takes place over there whereas Callisto is not geologically active.

This is the reason that probability of finding an impact crater will be more on Callisto than Io. As the craters might get filled with volcanic eruptions.

6 0
3 years ago
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