Part A. For this part, we use two equations for linear
motion:
<span>y = y0 + v0 t + 0.5 g t^2 --->
1</span>
<span>vf = v0 + g t --->
2</span>
First we solve for t using equation 1: y0 = 0 (initial
point at top), y = 250 m, v0 = 0 (at rest)
250 = 0.5 (9.8) t^2
t = 7.143 s
Now we solve for final velocity vf using equation 2:
vf = g t
vf = 9.8 (7.143)
vf = 70 m/s
Part B. First we solve for the time it takes for the sound
to reach the tourist.
t(sound) = 250 / 335 = 0.746 s
Therefore the total time would be:
t = 0.746 s + 0.300 s
t = 1.05 s
<span>Hence there is enough time for the tourist to get out
before the boulder hits him.</span>
Answer
given,
mass of satellite = 2400 Kg
speed of the satellite = 6.67 x 10³ m/s
acceleration of satellite = ?
gravitational force of the satellite will be equal to the centripetal force


Assuming the radius of circular orbit = 8.92 x 10⁶ m
now,

F = 11970.11 N
acceleration,


a = 4.98 m/s²
Answer:
Angle of incline is 20.2978°
Explanation:
Given that;
Gravitational acceleration on a planet a = 3.4 m/s²
Gravitational acceleration on Earth g = 9.8 m/s²
Angle of incline = ∅
Mass of the stone = m
Force on the stone along the incline will be;
F = mgSin∅
F = ma
The stone has the same acceleration as that of the gravitational acceleration on the planet.
so
ma = mgSin∅
a = gSin∅
Sin∅ = a / g
we substitute
Sin∅ = (3.4 m/s²) / (9.8 m/s²)
Sin∅ = 0.3469
∅ = Sin⁻¹( 0.3469 )
∅ = 20.2978°
Therefore, Angle of incline is 20.2978°
Answer:
See the answer below
Explanation:
The literal meaning for infinitesimal is for something to be small.
Other meanings include, but not limited to minute, insignificant, tiny, microscopic, minuscule.
Thus, the statement can be reconstructed by saying:
<em>Compared to the amount of carbon atoms on the earth, the amount of radioactive carbon atoms is small. </em>
Answer:
402 J/(kg ⁰C)
Explanation:
m = mass of the sample = 80.0 g = 0.080 kg
T₀ = Initial temperature of the sample = 25 ⁰C
T = Final temperature of the sample = 225 ⁰C
W = Amount of work done by the system = 346 J
U = Increase in internal energy = 6085 J
Q = Amount of heat given to the gas
Amount of heat is given as
Q = U + W
Q = 6085 + 346
Q = 6431 J
Heat received by sample is given as
Q = m c (T - T₀ )
inserting the values
6431 = (0.080) c (225 - 25)
c = 402 J/(kg ⁰C)