You drop a rock off a bridge. The rock's height, h (in feet above the water), after t seconds is modeled by h = – 16 t2 + 541. W

Question

pishuonlain [190]

3 years ago

7

You drop a rock off a bridge. The rock's height, h (in feet above the water), after t seconds is modeled by h = – 16 t2 + 541. W

hat is the height of the rock after 2 seconds?

Physics

1 answer:

marin [14] · Answer 1 · 2022-01-31T04:23:35+03:00

marin [14]3 years ago

5 0

<span>h ( t) = h(1 sec) = -16t^2 + 541

so h (2 sec) = -16*(2)^2 + 541 = -64 + 541 = <span>477 ft

Therefore, </span></span>the height of the rock after 2 seconds is 477 feet.

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