Question

You drop a rock off a bridge. The rock's height, h (in feet above the water), after t seconds is modeled by h = – 16 t2 + 541. What is the height of the rock after 2 seconds?

Answer 1

h ( t) = h(1 sec) = -16t^2 + 541

so h (2 sec) = -16*(2)^2 + 541 = -64 + 541 = 477 ft

Therefore, the height of the rock after 2 seconds is 477 feet.

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