Given conditions:
height of object = 7.5cmdistance of object from mirror = 14 cmfocus length = -7 cmimage distance = ?
Using mirror formula:
1/(focus length) = 1/(object distance) + 1/(image distance)
or, -1/7 = 1/14 + 1/(image distance)
or, image distance = -4.66cm (the image formed is a virtual image)
Also, magnification of image is:
image height /height of object = - image distance /object distance
or, image height = - image distance / object distance * height of object
or, image height = -(-4.66) / 14 * 7.5 = 2.49 = 3(nearest whole number)
Answer:
21.67 rad/s²
208.36538 N
Explanation:
= Final angular velocity = 
= Initial angular velocity = 78 rad/s
= Angular acceleration
= Angle of rotation
t = Time taken
r = Radius = 0.13
I = Moment of inertia = 1.25 kgm²
From equation of rotational motion
The magnitude of the angular deceleration of the cylinder is 21.67 rad/s²
Torque is given by
Frictional force is given by
The magnitude of the force of friction applied by the brake shoe is 208.36538 N
Answer:
107 °F
Explanation:
Given that
The temperature at sea level = 100°F
height ,h= 2000 feet
The average lapse rate = 3.5°F/1000 feet
Given that rise in temperature 3.5°F per 1000 feet.
1000 feet ⇒ 3.5°F
Given that 2000 feet
2000 feet ⇒ 3.5°F x 2 +100°F
2000 feet ⇒ 107 °F
Therefore the temperature will be 107 °F .
Voltage = 1.5V
Resistance = 1.5 ohm
Current = V/R = 1.5/1.5 = 1A
It has moved
(1.445) • (the acceleration) meters
