Make an equation system based on the problem
eg. a is the first number and b is the seond number
An equation for "<span>The sum of two numbers is 53" is
</span>⇒ a + b = 53
An equation for "<span>twice the first number minus three times the second number is 26"
</span>⇒ 2a - 3b = 26
<span>
Solve the equations by elimination and subtitution method
Eliminate a to find the value of b
a + b = 53 (multiplied by 2)
2a - 3b = 26
--------------------------------------
2a + 2b = 106
2a - 3b = 26
------------------- - (substract)
5b = 80
b = 80/5
b = 16
Subtitute the value of b to one of the equations
a + b = 53
a + 16 = 53
a = 53 - 16
a = 37
The numbers are 16 and 37</span>
Answer:
x² - 16xy + 64y²
Step-by-step explanation:
The difference of x and 8y is x - 8y
The square of the difference is (x - 8y)² = (x - 8y)(x - 8y)
Expand by multiplying each term in the second factor by each term in the first factor, that is
x(x - 8y) - 8y(x - 8y) ← distribute both parenthesis
= x² - 8xy - 8xy + 64y² ← collect like terms
= x² - 16xy + 64y²
The answer is 5.6! Hope I helped!
Answer:5
Step-by-step explanation: