Answer:
All their descendants will be heterozygous for the skin color, Bb, expressing blue skin.
Explanation:
<u>Available data</u>:
- Smurfette has light blue skin
- Her family is a "true bred" or "purebred" line.
- She married a boy who has light yellow skin
- blue skin is the dominant trait expressed by the B allele
- yellow skin is a recessive trait, expressed by the b allele
Cross: Smurfette x Husband
Parentals) BB x bb
Gametes) B B b b
Phenotypes) blue skin yellow skin
Punnett square)
B B
b Bb Bb
b Bb Bb
F1) 100% of the progeny will be heterozygous for the skin color, Bb
100% of the progeny will be blue-skinned.
Note: Although the progeny is blue-skinned, they are not true-bred anymore.
I am sorry but you did not include an attachment of the markings
Answer:
What specific question do you want answered so I can answer your question
Explanation:
There are multiple questions I have, what question do you want answered I need to know to assist you.
Answer:
carbons 3 and 4
Explanation:
Alcoholic fermentation is an anaerobic (non-oxygen-requiring) pathway capable of converting one mole of glucose (C6H12O6) into two moles of ethanol (C2H5OH) and two moles of carbon dioxide (CO2), producing during this process two moles of ATP. The overall chemical reaction is as follow: C6H12O6 (glucose) >> 2 C2H5OH (ethanol) + 2 CO2. During this process (fermentation), energy is obtained from the glycolysis process by which each glucose molecule is broken down into two pyruvate molecules (2 CH3COCOO−). Pyruvic acid is an organic acid that ionizes to produce a hydrogen ion and a molecule of pyruvate. Subsequently, this pyruvate is then converted into ethanol and CO2, generating NAD+, i.e., the oxidized form of nicotinamide adenine dinucleotide or NAD, which is required for glycolysis (and therefore to produce ATP). Moreover, dismutation refers to the redox reaction by which one compound with an intermediate oxidation state converts into two compounds. In consequence, the CO2 generated during fermentation arises from the dismutation of pyruvic acid. During this process, the major source of CO2 is carbon 3 (C3) and carbon 4 (C4) of the glucose as a result of the dismutation of pyruvate, and thereby these positions in the glucose molecule would the C14 label need to be incorporated.
Answer:
He should gather His data, then he should put it into a bar graph or a pie chart so the school can know what lunches they like best.
Explanation: