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yKpoI14uk [10]
3 years ago
15

When a cup is placed on a table, which force prevents the cup from falling to the ground?

Physics
2 answers:
pshichka [43]3 years ago
5 0
I believe it is normal force.
disa [49]3 years ago
3 0

Answer: Normal force prevents the cup from falling to the ground.

Explanation :

When a cup is placed on a table, the forces acting on the cup are the gravitational force and the normal force. The gravitational force acts in the downward direction while the normal force acts in an upward direction.

In the figure, N is the normal force and mg is the weight of an object acting in downward direction.

It is clear that the gravitational force is balanced by the normal force.

So, the correct option is (b) " normal force ".

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Two rocks of different masses are rolling down a hill at the same speed. Which rock (small one or big one) would have more kinet
aivan3 [116]

Answer:

Kinetic energy of bigger rock will be more than that of smaller one.

Explanation:

Kinetic energy of the rock is given by,

Kinetic energy = \frac{1}{2} m v^{2}

As velocity of both the rocks are same. Thus, kinetic energy is directly proportional to the mass of the rock

Kinetic energy ∝ mass

So, For greater mass kinetic energy will be greater and for smaller mass kinetic energy will be smaller.

Hence, Kinetic energy of bigger rock will be more than that of smaller one.

3 0
3 years ago
Read 2 more answers
Two particles collide, one of which was initially moving and the other initially at rest. Is it possible for both particles to b
solmaris [256]

Answer:

Not possible

Explanation:

Unless there's some extra external force to keep both particles at rest after the collision, the momentum must be conserved before and after the collision.

So before the collision, 1 particle is at rest, 1 not ->  total momentum is non-zero

After the collision, both particles are at rest -> total momentum is zero which is different from before.

Therefore this is not possible.

4 0
3 years ago
wheel rotates from rest with constant angular acceleration. Part A If it rotates through 8.00 revolutions in the first 2.50 s, h
Alex73 [517]

Answer:

x2 = 64 revolutions.

it rotate through 64 revolutions in the next 5.00 s

Explanation:

Given;

wheel rotates from rest with constant angular acceleration.

Initial angular speed v = 0

Time t = 2.50

Distance x = 8 rev

Applying equation of motion;

x = vt +0.5at^2 ........1

Since v = 0

x = 0.5at^2

making a the subject of formula;

a = x/0.5t^2 = 2x/t^2

a = angular acceleration

t = time taken

x = angular distance

Substituting the values;

a = 2(8)/2.5^2

a = 2.56 rev/s^2

velocity at t = 2.50

v1 = a×t = 2.56×2.50 = 6.4 rev/s

Through the next 5 second;

t2 = 5 seconds

a2 = 2.56 rev/s^2

v2 = 6.4 rev/s

From equation 1;

x = vt +0.5at^2

Substituting the values;

x2 = 6.4(5) + 0.5×2.56×5^2

x2 = 64 revolutions.

it rotate through 64 revolutions in the next 5.00 s

5 0
3 years ago
What is the resistance of an object to moving or to stopping
Marianna [84]
Inertia is the resistance of an object to moving or stopping
6 0
3 years ago
Read 2 more answers
As she climbs a hill a cyclist slows down from 25 mi/hr to 6mi/hr in 10 seconds what is her acceleration
vesna_86 [32]

|Acceleration| = (change in speed) / (time for the change).

Change in speed = (6 mi/hr - 25 mi/hr) = -19 mi/hr
Time for the change = 10 sec

|Acceleration| = (-19 mi/hr) / (10 sec) = -1.9 mile per hour per second

Admittedly, that's a rather weird unit.
Other units, perhaps more comfortable ones, are:

                 -6,840 mi/hr²

                   -2.79 feet/sec²

8 0
2 years ago
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