All categories

3 years ago

If size of an image is 10 cm and the magnification produced by a mirror is +1, what will be the size of object?

Physics

1 answer:

olya-2409 [2.1K]3 years ago

3 0

Answer:

h = 10 cm

Explanation:

The magnification produced by a mirror is given by :

$m=\dfrac{h'}{h}$

h' is the image size and h is the object size

We have, h = 10 cm, m = +1

So,

$m=\dfrac{h'}{h}\\\\h=\dfrac{10}{1}\\\\h=10\ cm$

So, the size off the object is same as that of the size of the image i.e. 10 cm.

You might be interested in

Which of the following are single-displacement reactions?

ololo11 [35]

Answer:

A & D

Explanation:

A single-displacement reaction is a chemical reaction whereby one element is substituted for another one in a compound and thereby generating a new element and also a new compound as products.

From the options, only options A & D fits this definition of single-displacement reactions.

For option D: Both left and hand and right hand sides each have one element and one compound. We can see that K is substituted from KBr to join Cl to form KCl and Br2 on the right hand side.

For option A: Both left and hand and right hand sides each have one element and one compound. We can see that OH is substituted from 2H2O to join Mg to form Mg(OH)2 and H2 on the right hand side.

The other options are not correct because they don't involve only and element and a compound on each side of the reaction.

6 0

2 years ago

Read 2 more answers

You need to determine the density of a ceramic statue. If you suspend it from a spring scale, the scale reads 28.4 NN . If you t

shtirl [24]

Answer:

2491.23 kg/m³

Explanation:

From Archimedes principle,

R.d = weight of object in air/ upthrust in water = density of the object/density of water

⇒ W/U = D/D' ....................... Equation 1

Where W = weight of the ceramic statue, U = upthrust of the ceramic statue in water, D = density of the ceramic statue, D' = density of water.

Making D the subject of the equation,

D = D'(W/U).................... Equation 2

Given: W = 28.4 N, U = lost in weight = weight in air- weight in water

U = 28.4 - 17.0 = 11.4 N,

Constant: D' = 1000 kg/m³.

Substitute into equation 2,

D = 100(28.4/11.4)

D = 2491.23 kg/m³

Hence the density of the ceramic statue = 2491.23 kg/m³

7 0

3 years ago

What force does the water exert (in addition to that due to atmospheric pressure) on a submarine window of radius 44.0 cm at a d

Butoxors [25]

Calculate the pressure due to sea water as density*depth.
That is,
pressure = (1025 kg/m^3)*((9400 m)*(9.8 m/s^2) = 94423000 Pa = 94423 kPa

Atmospheric pressure is 101.3 kPa
Total pressure is 94423 + 101.3 = 94524 kPa (approx)

The area of the window is π(0.44 m)^2 = 0.6082 m^2

The force on the window is
(94524 kPa)*(0.6082 m^2) = 57489.7 kN = 57.5 MN approx

3 0

4 years ago

What phenomenon causes colors of visible light to be separated by a prism?

Allushta [10]

Dispersion im pretty sure

6 0

3 years ago

Explain the effects of the endocrine system on development.

sladkih [1.3K]

" The endocrine system is the collection of glands that produce hormones that regulate metabilism, growth and developement, tissue function.." and others.

5 0

3 years ago