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slega [8]
3 years ago
8

An airplane flying due north at 90 km/h is being blown due west. The planes total velocity is 103 km/ hr north west. What is vel

ocity of the wind?
Physics
1 answer:
MA_775_DIABLO [31]3 years ago
4 0

Answer:

50.09 km/h

Explanation:

Given that an airplane flying due north at 90 km/h is being blown due west. The planes total velocity is 103 km/ hr north west.

What is velocity of the wind ?

The wind velocity can be calculated by using pythagorean theorem.

From the question,

Resultant Velocity R = 103 km/h

Plane velocity P = 90 km/h

Wind velocity W = ?

W^2 = R^2 - P^2

Substitutes all the parameters into the formula

W^2 = 103^2 - 90^2

W^2 = 10609 - 8100

W^2 = 2509

W = sqrt ( 2509 )

W = 50.09 km/h

Therefore, the velocity of the wind is 50.09 km/h

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A garage door opener has a power rating of 350 watts. If the door is in operation for 30 seconds, how many joules of energy are
Ksju [112]
Because of the hint we can conclude what equation we need to solve this problem. We have power and duration that means that we need to express energy:

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3 years ago
Suppose you exert a 400-N force on a wall but the wall does not move. The work you are doing on the wall is : unknown, because t
Ilya [14]

Answer:

W = 0 :The work done on the wall is zero,because the wall is not moving

Explanation:

Work theory

Work is the product of a force applied to a body and the displacement of the body in the direction of this force.

W= F*d Formula (1)

W: Work (Joules) (J)

F: force applied (N)

d=displacement of the body (m)

The work is positive (W+) if the force goes in the same direction of movement.

The work is negative (W-)if the force goes in the opposite direction to the movement

Data

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Problem development

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6 0
3 years ago
A capacitor with an initial potential difference of 185 V is discharged through a resistor when a switch between them is closed
GrogVix [38]

Answer:

  • a. \tau =  2.1161 s
  • b. V(18.8 \ s) = 0.0256 \ V

Explanation:

<h3>a.</h3>

The equation for the voltage V of  discharging capacitor in an RC circuit at time t is:

V(t) = V_0 e^{(- \frac{t}{\tau}) }

where V_0 is the initial voltage, and \tau is the time constant.

For our problem, we know

V_0 = 185 \ V

and

V(10 \ s) = V_0 e^{(- \frac{10 \ s}{\tau}) } = 1.64 \ V

So

185 \ V \ e^{(- \frac{10 \ s}{\tau}) } = 1.64 \ V

e^{(- \frac{10 \ s}{\tau}) } = \frac{1.64 \ V}{ 185 \ V }

ln (e^{(- \frac{10 \ s}{\tau}) } ) = ln (\frac{1.64 \ V}{ 185 \ V })

- \frac{10 \ s}{\tau}  = ln (\frac{1.64 \ V}{ 185 \ V })

\tau =  \frac{-10 \s}{ln (\frac{1.64 \ V}{ 185 \ V }) }

This gives us

\tau =  2.1161 s

and this is the time constant.

<h3>b.</h3>

At t = 18.8 s we got:

V(18.8 \ s) = 185 \ V  \ e^{(- \frac{18.8 \ s}{2.1161 s}) }

V(18.8 \ s) = 185 \ V \ e^{(- \frac{18.8 \ s}{2.1161 s}) }

V(18.8 \ s) = 0.0256 \ V

4 0
3 years ago
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