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slega [8]
3 years ago
8

An airplane flying due north at 90 km/h is being blown due west. The planes total velocity is 103 km/ hr north west. What is vel

ocity of the wind?
Physics
1 answer:
MA_775_DIABLO [31]3 years ago
4 0

Answer:

50.09 km/h

Explanation:

Given that an airplane flying due north at 90 km/h is being blown due west. The planes total velocity is 103 km/ hr north west.

What is velocity of the wind ?

The wind velocity can be calculated by using pythagorean theorem.

From the question,

Resultant Velocity R = 103 km/h

Plane velocity P = 90 km/h

Wind velocity W = ?

W^2 = R^2 - P^2

Substitutes all the parameters into the formula

W^2 = 103^2 - 90^2

W^2 = 10609 - 8100

W^2 = 2509

W = sqrt ( 2509 )

W = 50.09 km/h

Therefore, the velocity of the wind is 50.09 km/h

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You are standing on a bathroom scale in an elevator in a tall building. Your mass is
Oksanka [162]

Answer:

94 kg or 921.6 N

Explanation:

The velocity function is v(t) = 3t + 0.2t^2. The acceleration function, a(t), is the time derivative of the velocity function.

a(t) = \dfrac{d}{dt}v(t) = 3 + 0.4t

At t=4,

a(4) = 3 + 0.4\times4 = 3+1.6 =4.6\text{ m/s}{}^2

Because the elevator is going upwards, the net acceleration, a_N = g + a(4) where g us acceleration of gravity.

a_N = 9.8 + 4.6 = 14.4\text{ m/s}{}^2

The resultant weight is

W =m a_N =64\times14.4=921.6 \text{ N}

Since the bathroom scale is graduated in kg, it's reading is

m =\dfrac{W}{g}=\dfrac{921.6}{9.8}=94\text{ kg}

3 0
3 years ago
Charge q is accelerated starting from rest up to speed v through the potential difference V. What speed will charge q have after
adoni [48]

Answer: v = 1.19 * 10^{6} m/s

Explanation: q = magnitude of electronic charge = 1.609 * 10^{-19} c

mass of an electronic charge = 9.10 * 10^{-31} kg

V= potential difference = 4V

v = velocity of electron

by using the work- energy theorem which states that the kinetic energy of the the electron must equal the work done use in accelerating the electron.

kinetic energy = \frac{mv^{2} }{2},  potential energy = qV

hence, \frac{mv^{2} }{2} = qV

\frac{9.10 *10^{-31} * v^{2}  }{2} = 1.609 * 10^{-16} * 4\\\\\\\\9.10*10^{-31}  * v^{2} = 2 * 1.609 *10^{-16} * 4\\\\\\9.10 *10^{-31} * v^{2} = 1.287 *10^{-15} \\\\v^{2} = \frac{1.287 *10^{-15} }{9.10 *10^{31} } \\\\v^{2} = 1.414*10^{15} \\\\v = \sqrt{1.414*10^{15} } \\\\v = 1.19 * 10^{6} m/s

7 0
3 years ago
BRainliest if correct (if you don't know don't answer.)<br><br> 2
klemol [59]
Diagram B .... light shines through at an angle
6 0
3 years ago
Read 2 more answers
Imagine that you live in Maine. Currently there is a high-pressure area over Maine. If a low-pressure area moves in, how will th
miskamm [114]
I live in maine, windmills
7 0
3 years ago
One object (LaTeX: m_1m1) has a mass of 2 kg and moves with a speed of 9 m/s to the right. Another object (LaTeX: m_2m2) has a m
defon

Answer:

The correct answer is B

Explanation:

The moment of an object is the product of its mass by velocity, it is described by the equation

          p = mv

In this problem they give us the most body and speeds before and after the crash. We must define an environment with both bodies so that the forces during the crash have been internalized and the moment is preserved

         Δp = pf -p₀

         Δp = m v_{f} - m v₀

         Δp = 2 9 -2 1.5

         ΔP = 14.8 m/s

The correct answer is b

7 0
3 years ago
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