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valkas [14]
3 years ago
12

Green light has a frequency of about 6.00×1014s−1. what is the energy of green light? express your answer to three significant f

igures and include the appropriate units.
Physics
1 answer:
Digiron [165]3 years ago
4 0
Thank you for posting your question here at brainly. Below is the solution:

E = (h * c) / λ 
<span>E = h * f </span>
<span>E = (6.626E-34 J*s) * (6.00E14 Hz) </span>
<span>E = 397.5642E-21 Joules </span>
<span>E = 397.5642 zeptoJoules </span>
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An acorn falls from an oak tree. You note that it
Vaselesa [24]

Answer:9.8 m/s²

Explanation:

It was going at 9.8m/s² as this is the acceleration of an object due to gravity

when an object falls it accelerates at a consant and uniform speed which is 9.8m/s²

6 0
3 years ago
Two equal charges are 2m2m apart. If the charges and the distance are divided by two, how is the force between the charges affec
lara31 [8.8K]

Answer:

The force between the charges are not affected.

Explanation:

Given;

distance between two equal charges, R = 2m

The force between the charges is given by;

F = \frac{kq^2}{R^2}\\\\F_1 = \frac{kq_1^2}{R_1^2}\\\\When\ the \ charges \ and \ the \ distance \ are \ divided \ by \ two \ (q_2 = \frac{q_1}{2}, \ R_2 = \frac{R_1}{2} )\\\\ F_2 = \frac{kq_2^2}{R_2^2}\\\\F_2 = \frac{k(q_1/2)^2}{(R_1/2)^2}\\\\F_2= \frac{4k*q_1^2}{4*R_1^2}\\\\F_2 = \frac{k*q_1^2}{R_1^2}\\\\F_2 = F_1

Therefore, the force between the charges are not affected.

7 0
3 years ago
State the mathematical form of universal law of gravitation
Andrew [12]

Answer:

Newton's Universal Law of Gravitation: 'a simple equation, but devastatingly effective'. ... The equation says that the force (F) between two objects is proportional to the product of their masses (m1 and m2), divided by the square of the distance between them.

Explanation:

3 0
3 years ago
Quan sát sóng dừng trên sợi dây dài 60cm cố định hai đầu, thấy có 3 nút (bao gồm cả hai
stiks02 [169]

Answer:

Quan sát sóng dừng trên sợi dây dài 60cm cố định hai đầu, thấy có 3 nút (bao gồm cả hai

nút hai đầu) và 2 bụng. Bước sóng của sóng lan truyền trên sợi dây là:

7 0
3 years ago
A proton, traveling with a velocity of 1.6 × 106 m/s due east, experiences a maximum magnetic force of 8.0 × 10-14 N. The direct
uranmaximum [27]

Answer:

The magnitude of magnetic field is 0.312 T and direction of the magnetic field is out of the page.

Explanation:

Given:

Velocity of proton v = 1.6 \times 10^{6} \frac{m}{s}

Magnetic force F = 8 \times 10^{-14} N

Charge of proton q = 1.6 \times 10^{-19}C

The magnetic force experience by proton in magnetic field is given by,

    F =qvB \sin \theta

Here magnetic force experienced by proton is maximum so we take \sin \theta = 1

    F = qvB

    B = \frac{F}{qv}

    B = \frac{8 \times 10^{-14} }{1.6 \times 10^{-19} \times 1.6 \times 10^{6}  }

    B = 0.312 T

According to the left hand rule the direction of magnetic field is out of the page.

Therefore, the magnitude of magnetic field is 0.312 T and direction of the magnetic field is out of the page.

7 0
3 years ago
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