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3 years ago

Which of the following could be units of speed? A. m B. m/s C. m north D. degrees north

2 answers:

34kurt3 years ago

7 0

Since velocity is vector quantity, it'll depend on both direction as well as magnitude hence options C and D are rejected.
Speed = distance/time
Therefore, unit of velocity is m/s.

patriot [66]3 years ago

4 0

B. M/s because north is to to with locating areas degrees north is temperature and speed is not measure in meters

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VLD [36.1K]

Answer:

Option C

Explanation:

According to the formula

$\\ \boxed{\sf R=\rho\dfrac{\ell}{A}}$

If we use wide wire we increase the area of cross section so resistance decreases

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1 year ago

Solution A has a speciﬁc heat of 2.0 J/g◦C. Solution B has a speciﬁc heat of 3.8 J/g◦C. If equal masses of both solutions start

fgiga [73]

Answer: 2. Solution A attains a higher temperature.

Explanation: Specific heat simply means, that amount of heat which is when supplied to a unit mass of a substance will raise its temperature by 1°C.

In the given situation we have equal masses of two solutions A & B, out of which A has lower specific heat which means that a unit mass of solution A requires lesser energy to raise its temperature by 1°C than the solution B.

Since, the masses of both the solutions are same and equal heat is supplied to both, the proportional condition will follow.

We have a formula for such condition,

$Q=m.c.\Delta T$ .....................................(1)

where:

$\Delta T$ = temperature difference

Q= heat energy

m= mass of the body

c= specific heat of the body

Proving mathematically:

According to the given conditions

we have equal masses of two solutions A & B, i.e. $m_A=m_B$

equal heat is supplied to both the solutions, i.e. $Q_A=Q_B$

specific heat of solution A, $c_{A}=2.0 J.g^{-1} .\degree C^{-1}$

specific heat of solution B, $c_{B}=3.8 J.g^{-1} .\degree C^{-1}$

$\Delta T_A$ & $\Delta T_B$ are the change in temperatures of the respective solutions.

Now, putting the above values

$Q_A=Q_B$

$m_A.c_A. \Delta T_A=m_B.c_B . \Delta T_B\\\\2.0\times \Delta T_A=3.8 \times \Delta T_B\\\\ \Delta T_A=\frac{3.8}{2.0}\times \Delta T_B\\\\\\\frac{\Delta T_{A}}{\Delta T_{B}} = \frac{3.8}{2.0}>1$

Which proves that solution A attains a higher temperature than solution B.

7 0

3 years ago

The circuit below shows some of the circuity in a small toy robot. When the circuit is on, the robot moves its arms (the motor)

djyliett [7]

Answer:

dear can you provide the circuit of the robot

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3 years ago

The component of acceleration perpendicular to an object’s velocity tells us: A. How the object’s speed changes. B. The influenc

vesna_86 [32]

Answer:

Option C is correct.

The component of acceleration perpendicular to an object’s velocity tells us How the object’s direction changes.

Explanation:

This acceleration is called radial/tangential acceleration. It is the reason why a body moving in circular motion with constant velocity can be said to also be accelerating because its direction is continuously changing. The acceleration is usually directed towards the centre of the circular motion of the body or trying to throw the body off its circular motion path.