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Tamiku [17]
2 years ago
13

In a face-centered cubic structure, every atom has twelve neighbors. which arrangement of balls serves as the best model for thi

s structure? twelve balls arranged equally apart from each other around a circle eight balls at the corners of a cube eight balls at the corners of a cube, and one ball in the center of the cube eight balls at the corners of a cube, and six balls in the centers of the cube's faces description

Chemistry
1 answer:
liberstina [14]2 years ago
8 0
The image attached below is the correct representation of a face-centered cubic unit cell model. To create this model, you have to place 6 balls in the centers of each of the cube's faces and 1 ball for every corner of the cube which sums up to 8 balls. Therefore, the answer is: <span><em>eight balls at the corners of a cube, and six balls in the centers of the cube's faces.</em></span>

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3 years ago
Given the following balanced equation, if the rate of O2 loss is 3.64 × 10-3 M/s, what is the rate of formation of SO3? 2 SO2(g)
Fynjy0 [20]

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Rate of formation of SO₃ [\frac{d[SO_{3}] }{dt}] = 7.28 x 10⁻³ M/s

Explanation:

According to equation   2 SO₂(g) + O₂(g) → 2 SO₃(g)

Rate of disappearance of reactants = rate of appearance of products

                     ⇒ -\frac{1}{2} \frac{d[SO_{2} ]}{dt} = -\frac{d[O_{2} ]}{dt}=\frac{1}{2} \frac{d[SO_{3} ]}{dt}  -----------------------------(1)

    Given that the rate of disappearance of oxygen = -\frac{d[O_{2} ]}{dt} = 3.64 x 10⁻³ M/s

             So the rate of formation of SO₃ [\frac{d[SO_{3}] }{dt}] = ?

from equation (1) we can write

                                   \frac{d[SO_{3}] }{dt} = 2 [-\frac{d[O_{2}] }{dt} ]

                                ⇒ \frac{d[SO_{3}] }{dt} = 2 x 3.64 x 10⁻³ M/s

                                ⇒ [\frac{d[SO_{3}] }{dt}] = 7.28 x 10⁻³ M/s

∴ So the rate of formation of SO₃ [\frac{d[SO_{3}] }{dt}] = 7.28 x 10⁻³ M/s

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E. All of the above.

then the ans is E

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