All categories

2 years ago

Need help please

Chemistry

1 answer:

8090 [49]2 years ago

7 0

Answer:

Explanation:

because when you crush an ice it would break into peace's and the ice would not be a solid

You might be interested in

Are these ramen noodles expired?

laiz [17]

Answer:

i think so

Explanation:

just eat them anyways

6 0

3 years ago

Read 2 more answers

How much energy is released by the decay of 3 grams of 230Th in the following reaction 230 Th - 226Ra + "He (230 Th = 229.9837 g

Serhud [2]

Answer: The energy released for the decay of 3 grams of 230-Thorium is $2.728\times 10^{-15}J$

Explanation:

First we have to calculate the mass defect $(\Delta m)$ .

The equation for the alpha decay of thorium nucleus follows:

$_{90}^{230}\textrm{Th}\rightarrow _{88}^{226}\textrm{Ra}+_2^{4}\textrm{He}$

To calculate the mass defect, we use the equation:

Mass defect = Sum of mass of product - Sum of mass of reactant

$\Delta m=(m_{Ra}+m_{He})-(m_{Th})$

$\Delta m=(225.9771+4.008)-(229.9837)=1.4\times 10^{-3}amu=2.324\times 10^{-30}kg$

(Conversion factor: $1amu=1.66\times 10^{-27}kg$ )

To calculate the energy released, we use Einstein equation, which is:

$E=\Delta mc^2$

$E=(2.324\times 10^{-30}kg)\times (3\times 10^8m/s)^2$

$E=2.0916\times 10^{-13}J$

The energy released for 230 grams of decay of thorium is $2.0916\times 10^{-13}J$

We need to calculate the energy released for the decay of 3 grams of thorium. By applying unitary method, we get:

As, 230 grams of Th release energy of = $2.0916\times 10^{-13}J$

Then, 3 grams of Th will release energy of = $\frac{2.0916\times 10^{-13}}{230}\times 3=2.728\times 10^{-15}J$

Hence, the energy released for the decay of 3 grams of 230-Thorium is $2.728\times 10^{-15}J$

5 0

3 years ago

When an aqueous solution of magnesium nitrate is mixed with an aqueous solution of potassium carbonate, ____________.?

spin [16.1K]

Ca(NO3)2 + Na2CO3 = CaCO3 + 2NaNO3
Yes a precipitate of Calcium Carbonate is formed since it is insoluble in water.
Mol Wt of Calcium Nitrate is 164. And that of Calcium Carbonate is 100.
One mole of Calcium Nitrate produces one mole of Calcium Carbonate.
i.e. 164 gms will produce 100gms of precipitate
So, 1.74gms of Calcium Carbonate will be obtained from 2.85gms Calcium Nitrate present in the original solution.

3 0

3 years ago

Explain how you would use the IR spectra to characterize ferrocene, acetyl ferrocene and diacetyl ferrocene.

motikmotik

Answer:

..........................

Explanation:

........................

6 0

3 years ago

Ammonium Phosphate (NH4)3PO4 is a strong electrolyte. What will be the concentration of all the ions in a 0.9 M solution of ammo

katrin2010 [14]

There are 3 moles of

$NH_4^+$

per 1 mole of salt and 1 mole of

$PO_{4}^{3-}$

per mole of salt, the total ionic concentrations must be

$2.7 M$ of $NH_4^{+}$ , and $0.9 M$ of $PO_4^{3-}$

3 0

3 years ago