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MArishka [77]
1 year ago
7

Which volume of ethane gas, in cm3 , will produce 40cm3 of carbon dioxide gas when mixed with 140cm3 of oxygen gas, assuming the

reaction goes to completion
Chemistry
1 answer:
Gemiola [76]1 year ago
7 0

The volume of ethane gas, C₂H₆ in cm³ that will react to produce 40 cm³ of CO₂ is 20 cm³

<h3>Balanced equation </h3>

2C₂H₆ + 7O₂ —> 4CO₂ + 6H₂O

From the balanced equation above,

4 cm³ of CO₂ were obtained from 2 cm³ of C₂H₆

<h3>How to determine the volume of C₂H₆ needed </h3>

From the balanced equation above,

4 cm³ of CO₂ were obtained from 2 cm³ of C₂H₆

Therefore,

40 cm³ of CO₂ will be obtain from = (40 × 2) / 4 = 20 cm³ of C₂H₆

Thus, 20 cm³ of C₂H₆ are required for the reaction.

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

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Answer:

The answer to your question is: SiCl₄

Explanation:

Data

amount of Si      1.71 g

amount of Cl     8.63 g

MW Si = 28 g

MW Cl = 35.5

Process (rule of three)

For Si                                                        For Cl

        28 g of Si ------------------ 1 mol                      35.5 g of Cl --------------- 1 mol

          1.71g of Si  ---------------   x                              8.63 g of Cl --------------  x

         x = 1.71 x 1 / 28 = 0.06 mol                          x = 8.63 x 1 / 35.5 = 0.24 mol

Now, divide both results by the lowest of them.

Si = 0.06 mol / 0.06 = 1 molecule of Si     Cl = 0.24 / 0.06 = 4 molecules of Cl

Finally

                     Si₁ Cl₄ or SiCl₄

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