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MArishka [77]
2 years ago
7

Which volume of ethane gas, in cm3 , will produce 40cm3 of carbon dioxide gas when mixed with 140cm3 of oxygen gas, assuming the

reaction goes to completion
Chemistry
1 answer:
Gemiola [76]2 years ago
7 0

The volume of ethane gas, C₂H₆ in cm³ that will react to produce 40 cm³ of CO₂ is 20 cm³

<h3>Balanced equation </h3>

2C₂H₆ + 7O₂ —> 4CO₂ + 6H₂O

From the balanced equation above,

4 cm³ of CO₂ were obtained from 2 cm³ of C₂H₆

<h3>How to determine the volume of C₂H₆ needed </h3>

From the balanced equation above,

4 cm³ of CO₂ were obtained from 2 cm³ of C₂H₆

Therefore,

40 cm³ of CO₂ will be obtain from = (40 × 2) / 4 = 20 cm³ of C₂H₆

Thus, 20 cm³ of C₂H₆ are required for the reaction.

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

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Verizon [17]

The number of moles of Nitrogen : == 7.975

<h3>Further explanation </h3>

Given

9.60x10²⁴ molecules  of nitrogen dioxide (NO2)

Required

The number of moles

Solution

Reaction

N2 + 2O2 → 2NO2

moles of NO2 :

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From the equation, mol N2 :

= 1/2 x mol NO2

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= 7.975

The number of molecules :

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= 4.816 x 10²⁴

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