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jolli1 [7]
2 years ago
14

(hurry will give brainliest)What element that has 5 Valence Electrons and 4 energy levels?

Chemistry
1 answer:
abruzzese [7]2 years ago
8 0

Answer:

arsenic (As)

Explanation:

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There are many compounds that contribute to the overall aroma of a banana. The primary compound is called isoamyl acetate and co
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Explanation:

Let the mass of isoamyl acetate be 100g.

Moles of Carbon = 60.58/12 = 5.048mol

Moles of Hydrogen = 7.07/1 = 7.07mol

Moles of Oxygen = 32.28/16 = 2.018mol

Mole Ratio of C : H : O

= 5.048 : 7.07 : 2.018

= 5 : 7 : 2.

Hence the empirical formula of isoamyl acetate is C5H7O2.

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Which is a practical application of boiling-point elevation?
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Boiling-point is the point of a pure liquid matter starts to evaporate and change into gaseous phase. It is where the set of conditions such as the pressure and temperature enough to do so. Boiling-point elevation, on the other hand, is the phenomenon of which the boiling point of a pure liquid matter is elevated because of the dissolved substances. A great example would be the boiling point of a distilled water (pure water) which is lesser than the boiling point of a sea water because of the dissolved salts. A pure water boils at 100°C at atmospheric pressure while a salt water boils at higher temperature than 100°C at the same pressure. Thus, the answer is D.
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3 years ago
How many neutrons would an atom of fluorine have?
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6 0
2 years ago
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To a 25.00 mL volumetric flask, a lab technician adds a 0.150 g sample of a weak monoprotic acid, HA , and dilutes to the mark w
Elis [28]

<u>Answer:</u> The number of moles of weak acid is 4.24\times 10^{-3} moles.

<u>Explanation:</u>

To calculate the moles of KOH, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}\text{Volume of solution (in L)}}

We are given:

Volume of solution = 43.81 mL = 0.04381 L      (Conversion factor: 1L = 1000 mL)

Molarity of the solution = 0.0969 moles/ L

Putting values in above equation, we get:

0.0969mol/L=\frac{\text{Moles of KOH}}{0.04381}\\\\\text{Moles of KOH}=4.24\times 10^{-3}mol

The chemical reaction of weak monoprotic acid and KOH follows the equation:

HA+KOH\rightarrow KA+H_2O

By Stoichiometry of the reaction:

1 mole of KOH reacts with 1 mole of weak monoprotic acid.

So, 4.24\times 10^{-3}mol of KOH will react with = \frac{1}{1}\times 4.24\times 10^{-3}=4.24\times 10^{-3}mol of weak monoprotic acid.

Hence, the number of moles of weak acid is 4.24\times 10^{-3} moles.

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