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mezya [45]
3 years ago
13

If all materials were good conductors of heat, would people and animals be able to live in cold climates? Explain your answer.

Chemistry
1 answer:
miss Akunina [59]3 years ago
6 0
Yes we would be able to live in cold climates.
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What are the observable properties of salt and rocks, and explain how you used empirical evidence to explain that mixtures of so
777dan777 [17]

Answer:

Appearance. Pure rock salt is colorless. However, when found underground it is generally not completely pure, so may have yellow, red, gray or brown hues. It is either transparent or translucent and when you shine a light on it, its luster is vitreous, meaning it appears shiny and glassy.

Explanation:

6 0
2 years ago
The jet stream is one of the key winds that moves air masses. in which direction does the jet stream in the united state general
OleMash [197]

The jet stream is one of the key winds that moves air masses at the direction from west to east it moves.

<h3>What are jet streams?</h3>

Jet streams are strong winds which are flow in the form of narrow bands in the upper part of the atmosphere. On the earth these winds are flows near the altitude of the tropopause. These winds carries weather systems and blows toward the colder northern air and due to the rotation of earth, its direction is from west to east.

Hence jet streams move winds from west to east direction.

To know more about jet streams, visit the below link:
brainly.com/question/791542

7 0
2 years ago
an amber alert object is placed in 50 mL of water in the water level rises 72 ml. What is the volume of the object?​
Ilya [14]

Answer:

72 ml-50 ml =22 ml is the volume of the object

Explanation:

7 0
3 years ago
Initial Concentration mol/L[A] Initial Concentration mol/L[B] Initial Rate mol/Ls 0.20 0.10 20 0.20 0.20 40 0.40 0.20 160 Given
zimovet [89]
The generalized rate expression may be written as:
r = k[A]ᵃ[B]ᵇ

We may determine the order with respect to B by observing the change in rate when the concentration of B is changed. This can be done by comparing the first two runs of the experiment, where the concentration of A is constant but the concentration of B is doubled. Upon doubling the concentration of B, we see that the rate also doubles. Therefore, the order with respect to concentration of B is 1.
The same can be done to determine the concentration with respect to A. The rate increases 4 times between the second and third trial in which the concentration of B is constant, but that of A is doubled. We find that the order with respect to is 2. The rate expression is:

r = k[A]²[B]
4 0
3 years ago
Read 2 more answers
How many atoms of mercury are present in 3.4 cubic centimeters of liquid mercury? the density of mercury is 13.55 g/cc?
maks197457 [2]

Answer:

             1.37 × 10²³ Atoms of Mercury  

Solution:

Step 1: Calculate Mass of Mercury using following formula,

                               Density  =  Mass ÷ Volume

Solving for Mass,

                               Mass  =  Density × Volume

Putting values,

                               Mass  =  13.55 g.cm⁻³ × 3.4 cm³                ∴ 1 cm³ = 1 cc

                               Mass  =  46.07 g

Step 2: Calculating number of Moles using following formula;

                               Moles  =  Mass ÷ M.mass

Putting values,

                               Moles  =  46.07 g ÷ 200.59 g.mol⁻¹

                               Moles  =  0.229 mol

Step 3: Calculating Number of Atoms using following formula;

                               Number of atoms  =  Moles × 6.022 ×10²³

Putting value of moles,

                               Number of Atoms  =  0.229 mol × 6.022 × 10²³

                              Number of Atoms  =  1.37 × 10²³ Atoms of Hg

8 0
3 years ago
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