Answer:
Moles of NO₂ = 0.158
Explanation:
SO 2 ( g ) + NO 2 ( g ) ⇄ SO 3 ( g ) + NO ( g )
According to the law of mass equation
=
⇒ 3.10 = At equilibrium [SO₃] = [NO]
⇒ [NO₂] =
⇒ [NO₂] = 0.158
So. number of moles of NO₂ at equilibrium added = 0.158
.dhdwbhdxqbsajxnx n sg
they are transfer from the towers
1,150.62 millimeters