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pogonyaev
3 years ago
8

Select all of the numbers that are correctly written in scientific notation. 10.8\times10^{-3}10.8×10 −3 0.54\times10^60.54×10 6

1\times10^{-4}1×10 −4 7.6\times10^{2.5}7.6×10 2.5 9.8\times10^59.8×10 5
Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
7 0

Answer:

<h2><em>1×10⁻⁴ and 9.8×10⁵</em></h2>

Step-by-step explanation:

The standard form of writing a scientific notation is expressed as a.b*10^n where a, b and n are integers. Note that a, b and n cannot be a fraction. When writing in scientific notation, the value of 'a' must not be equal to zero and it must not be a 'two digits values' but just 'a digit value'.

<em>Based on the above conclusion, the following numbers are correctly written in scientific notation.</em>

<em>1×10⁻⁴ and 9.8×10⁵</em>

- The expression 10.8×10 −3 is not correctly written because the value of a on comparison is a two digits number i.e 10.

- Also, 0.54×10^6 is not correctly written because a is zero on comparison

- 7.6×10 2.5 is not correctly written because the power is a decimal number i.e 2.5. We must only have an integer as the degree.

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If the radius of circle O is 10 inches and m∠UON=90∘, what is the area of sector URN⌢?
arsen [322]

Answer:

  75π in²

Step-by-step explanation:

The shaded sector is 3/4 of the circle. We can use the area formula for a circle to find the area of the whole circle, then multiply that result by 3/4.

  A = πr² = π(10 in)² = 100π in²

Then the area of 3/4 of the circle is ...

  3/4·A = (3/4)·100π in² = 75π in²

6 0
3 years ago
Nora's paper airplane flew 9 1/6 feet. That was 2 3/4 feet farther than Max's plane flew. Write and solve an equation to show ho
stepan [7]

Answer:

Max's paper airplane flew \frac{77}{12} feet or 6\frac{5}{12} feet.

Step-by-step explanation:

As Nora's paper airplane flew 9 1/6 feet

i.e.

9\frac{1}{6}=\frac{55}{6}

Nora's paper was farther than Max's plane flew by = 2 3/4 feet

i.e.

2\frac{3}{4}=\frac{11}{4}

Thus the equation to show how far Max's paper airplane flew is:

\:\:9\frac{1}{6}-2\frac{3}{4}

=\frac{55}{6}-\frac{11}{4}

\mathrm{Least\:Common\:Multiplier\:of\:}6,\:4:\quad 12

\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}

=\frac{110}{12}-\frac{33}{12}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

=\frac{110-33}{12}

\mathrm{Subtract\:the\:numbers:}\:110-33=77

=\frac{77}{12}

=6\frac{5}{12}

Therefore, Max's paper airplane flew \frac{77}{12} feet or 6\frac{5}{12} feet.

6 0
3 years ago
Maria finds a local gym that advertises 67 training sessions for $2052. Find the cost of 153 training sessions.
Ann [662]

Answer:

Cost\ of\ 153\ training\ sessions\ =\$4685.9\approx\$4686

Step-by-step explanation:

Cost\ of\ 67\ training\ sessions\ =\$2052\\\\Cost\ of\ 1\ training\ sessions\ =\frac{Total\ cost}{Total\ training\ sessions}\\\\Cost\ of\ 1\ training\ sessions\ =\frac{2052}{67}\\\\Cost\ of\ 153\ training\ sessions\ =153\times cost\ of\ 1\ training\ sessions\ \\\\Cost\ of\ 153\ training\ sessions\ =153\times\frac{2052}{67}=4685.9\\\\Cost\ of\ 153\ training\ sessions\ \$4685.9\approx4686

7 0
3 years ago
Calculate the total interior angle of an octagon​
slava [35]
<h2>1080°</h2><h2></h2>

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hope that helps !

8 0
3 years ago
Read 2 more answers
Consider the quadratic function f(x) = 2x2 – 8x – 10. The x-component of the vertex is . The y-component of the vertex is . The
mr_godi [17]
F(x) = 2x² - 8x - 10.
This is a parabola open upward (since a>0) with an axis of symmetry = -b/2a:
a) axis of symmetry: x = -(-8)/(2*2) = 8/4 = 2. Then x = 2, which is the x component of the vertex
b) for x =  2, f(x) = f(2) = - 18 (component of y of the vertex)
c) VERTEX(2, - 18)
d) DISCRIMINENT: b² - 4.a.c = 64 - 4*2*(-10) = 144
8 0
3 years ago
Read 2 more answers
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