This question involves the concepts of Newton's Law of Gravitation and mass.
The force on Procyon A from Procyon B will be "equal" to the force on Procyon B from Procyon A, which has a value of "3.75 x 10²⁶ N".
Applying Newton's Law of Gravitation, we can find the force on Procyon A from Procyon B, which is equal to the force on Procyon B from Procyon A:
where,
F = force = ?
G = universal gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg²
m₁ = mass of Procyon A = 3 x 10³⁰ kg
m₂ = mass of Procyon B = (2.5)(3 x 10³⁰ kg) = 7.5 x 10³⁰ kg
r = distance between them = 2 x 10¹² m
Therefore,
<u>F = 3.75 x 10²⁶ N</u>
Learn more about Newton's Law of Gravitation here:
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Answer:
Explanation:
We shall apply law of conservation of momentum to know the Speed of northward moving vehicle before collision to check the veracity of driver's statement .
Let v be the velocity of composite mass after collision
Applying law of conservation of momentum in north direction
m v₂ = 2m v sin55.08
Applying law of conservation of momentum in east direction
m x 13 = 2m v cos55.08
Dividing these two equations
v₂ / 13 = tan55.08
v₂ = 13 tan55.08
= 18.62 m/s
= (18.62 x60 x 60) / 1000
= 67 km/h
= 67 x 5/8 mi/h
= 42 mi/h
So he is lieing.
An electric field is an electric property associated with each point in space when charge is present in any form.
It's the measure of the average kinetic energy
KE=1/2*m*v^2
So 480=1/2 * m * 8^2
480=1/2 * m * 64
480=32 * m
480/32=m
15=m
