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nata0808 [166]
3 years ago
7

Two forces are acting on a 2.0 kg object that moves with acceleration 6.0 m/s2 in the positive y-direction. If one of the forces

acts in the positive x-direction and has magnitude of 22 N, what is the magnitude of the other force (in N)
Physics
1 answer:
Strike441 [17]3 years ago
3 0

Answer:

12N

Explanation:

We are given that one of the forces are acting only in the horizontal x-direction. As a force must be applied on an object of mass in order to cause acceleration, the 6.0ms^-2 acceleration is due to the non-horizontal force acting on the 2.0kg object.

Using Newton's Second Law of motion; we know that for a constant mass, force is equal to mass times acceleration, F=ma.

Assuming the other force is acting only in the vertical direction (question doesn't specify, thus we are finding the minimum force to cause this acceleration):

F= 2.0kg * 6.0ms^-2

F=12.0 kgms^-2

F=12 N

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Answer with Explanation:

We are given that

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We know that magnetic flux

\phi=BA

Emf ,E=\mid \frac{d\phi}{dt}\mid =\mid\frac{d(BA}{dt}\mid =\mid A\frac{dB}{dt}=400\times 10^{-4}\times \frac{4t-2t^2}{dt}\mid =\mid400\times 10^{-4}\times(4-4t)\mid

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Current, I=\frac{\mid 400\times 10^{-4}(4-4t)\mid }{0.1}=1.6\mid (1-t)\mid

Substitute t=0 s

Then, I=1.6\mid (1-0)\mid=1.6 A

Substitute t=1 s

Then, I=1.6\mid (1-1)\mid=0

Substitute

t=2 s

Current, I=1.6\mid(1-2)\mid=1.6 A

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