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nata0808 [166]
3 years ago
7

Two forces are acting on a 2.0 kg object that moves with acceleration 6.0 m/s2 in the positive y-direction. If one of the forces

acts in the positive x-direction and has magnitude of 22 N, what is the magnitude of the other force (in N)
Physics
1 answer:
Strike441 [17]3 years ago
3 0

Answer:

12N

Explanation:

We are given that one of the forces are acting only in the horizontal x-direction. As a force must be applied on an object of mass in order to cause acceleration, the 6.0ms^-2 acceleration is due to the non-horizontal force acting on the 2.0kg object.

Using Newton's Second Law of motion; we know that for a constant mass, force is equal to mass times acceleration, F=ma.

Assuming the other force is acting only in the vertical direction (question doesn't specify, thus we are finding the minimum force to cause this acceleration):

F= 2.0kg * 6.0ms^-2

F=12.0 kgms^-2

F=12 N

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Explanation:

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T = mg

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C ) If the gymnast climbs up the rope with an upward acceleration of magnitude 0.600 m/s2

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T =  mg + m a

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She does a work of 689.44 J in the snow.

Explanation:

A force is said to do work when it alters the state of motion of a body. The work of the force on that body will be equivalent to the energy needed to move it.

In other words, Work is a form of energy transmission between bodies. In order to carry out work, a force must be exerted on a body and it must move.

The work is equal to the product of the force times the distance and the cosine of the angle that exists between the direction of the force and the direction that the moving point or object travels:

W= F*d* cos Ф

Work W is measured in joules (J), force is measured in newtons (N), and displacement in meters (m).

In this case:

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Replacing:

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Solving:

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<u><em>She does a work of 689.44 J in the snow.</em></u>

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