Question

an oscilloscope has a time/div setting of 50ms and there are 10 divisions on the time scale. a sine wave on the oscilloscope display has exactly three full cycles of the sine wave that fit on the 10 divisions. what is the frequency of the wave? show your work.

Answer 1

Answer:

The frequency is f = 6Hz

Explanation:

Given

         The time division  setting is  $d_t =50ms = 50*10^{-3}s$

         The number of division is  $n= 10$

The total time for 10 division can be mathematically obtained as

         $T_{total} = 10 *50*10^{-3}$

                 $=500 *10^{-3}s$

From the question the time for 3 cycle is

        $T_{total} = 500*10^{-3}s$

Then the for one cycle which equivalent to the Period$(T)$  $= \frac{T_{total}}{3}$

                                                               $= \frac{500 *10^{-3}}{3}$

The frequency is generally given as    $f = \frac{1}{period} = \frac{1}{T}$

    Now substituting values we have  

                              $f = \frac{3}{500 *10^{-3}}$

                                 $= 6Hz$