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Lemur [1.5K]
3 years ago
13

R = (2+2+1) i - (t+1)] + t3 k what is the direction of initial velocity

Physics
1 answer:
Wittaler [7]3 years ago
4 0

Answer:

In the - j direction, that is negative of the y-axis

Explanation:

As typed in the question, the position of the object is given by the expression in three component ( i, j, k) form:

r (t) = 5  i  - (t + 1 )  j  + t^3  k

and since the velocity is the derivative of position with respect to time, by doing the derivative of this expression we get:

v(t) = 0  i  -  1  j   +3 t^2  k

which for the initial velocity requested (that is at time zero) we have:

v(t) = 0  i  -  1  j   +3 (0)^2  k = = 1  j

Then the direction of the initial velocity is entirely in the direction of the j versor, that is pointing to the negative of the y-axis.

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What is the answer to this question
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Create a series circuit with a 10-volt battery and four 10-ohm resistors, as shown. Measure the current. A. Based on the voltage
iogann1982 [59]

Answer:

0.25 A

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Explanation:

The first, and perhaps most important, the relationship between current, voltage, and resistance is called Ohm's Law, discovered by Georg Simon Ohm and published in his 1827 paper. Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points. Introducing the constant of proportionality, the resistance, one arrives at the usual V=IR. Any Electrical device or component that obeys “Ohms Law” that is, the current flowing through it is proportional to the voltage across it ( I α V ), such as resistors or cables, are said to be “Ohmic” in nature.

Since we are not in a laboratory, we can not experimentally measure the current but it can be calculated from ohm's law.

Given that the four resistors are connected in series and

Req= R1 + R2 + R3 + R4

Since all are four ohm resistors

Req= 10 + 10+10+10 = 40ohms

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V= 10 V

R= 40ohms

I= ???

From;

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I= 10/40

I= 0.25 A

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