Molar mass KBr = 119 g/mol
Volume in liters: 250.0mL / 1000 => 0.25 L
n = M x V
n = 1.20 x 0,25 => 0.3 moles of KBr
Therefore:
1 mole KBr ----------- 119 g
0.3 moles KBr -------- ??
0.3 x 119 / 1 => 35.7 g of KBr
C3H8+3O2--->3CO2+8H
Therefore for every 1:3 there are 3 Carbon dioxides that form. That means find the limiting reactant from the two reactants.
5.5g(1mole C3H8/44.03g of C3H8)=0.1249 moled of C3H8 and if for every one C3H8 we can form three CO2. We can assume 0.3747 miles of CO2 will be produced.
15g of O2(1 mole O2/32g of O2)=0.4685moles O2 and if for every three O2 we can produce three CO2 we may assume a 1:1 ratio.
This means C3H8 will be your limiting reactant. Therefore 0.3747 moles of CO2 will be produced.
0.3747 moles of CO2(48.01 g of CO2/1 mole of CO2)= 17.99 grams of CO2
Answer:
#1 Exposition
#2 Background information
#3 Complication
this is right unless you're speaking of theme plot conflict climax falling action or conclusion
Answer:
The correct answer is
B.action potential; sodium
Explanation:
Action potential
Nerve action potentials are initiated and propagated in an all or nothing fashion. The all-or nothing action potential is initiated when the membrane potential threshold value is reached
Sodium
Voltage-gated Na⁺ ions membrane channels open enabling an influx of sodium ions to rapidly enter the cell, raising the membrane potential up to +40 mV
Depolarization in the neuron is based ion exchange channels opening to allow the rapid influx of sodium ions (Na⁺) and the efflux of potassium ions (K⁺)
The neuronal responds rapidly and for short periods to the activation of an ion channel receptor by a drug or natural neurotransmitter is rapid rel
The number of moles of CO₂ that is produced when burning 6.0 mol of ethanol is 12 mol.
<h3>What is Balanced Chemical Equation ?</h3>
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
Now we have to write the balanced equation
C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O
We can see that every 1 mole of ethanol we will get 2 mole of CO₂.
So 6.0 mol of ethanol we will get = 6.0 × 2.0
= 12 mol of CO₂
Thus from the above conclusion we can say that The number of moles of CO₂ that is produced when burning 6.0 mol of ethanol is 12 mol.
Learn more about the Balanced Chemical Equation here: brainly.com/question/26694427
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