Answer:
V = 50 volts
Explanation:
Given that,
Resistance, R = 10 ohms
Current, I = 5 A
We need to find the potential difference across the circuit. We know that,
V = IR
Put all the values,
V = 5 × 10
V = 50 volts
Hence, the potential difference is equal to 50 volts.
Answer:
is the drop in the water temperature.
Explanation:
Given:
- mass of ice,

- mass of water,

Assuming the initial temperature of the ice to be 0° C.
<u>Apply the conservation of energy:</u>
- Heat absorbed by the ice for melting is equal to the heat lost from water to melt ice.
<u>Now from the heat equation:</u>

......................(1)
where:
latent heat of fusion of ice 
specific heat of water 
change in temperature
Putting values in eq. (1):

is the drop in the water temperature.
Answer:
Despite being such prominent feature on our planet, much of the mid-ocean ridge system remains a mystery. While we have mapped about half of the global mid-ocean ridge in high resolution, less than one percent of the mid-ocean ridge has been explored in detail using submersibles or remotely operated vehicles. so therefore we do not have enough information about them to know what will happen
Explanation:
A mid-ocean ridge or mid-oceanic ridge is an underwater mountain range, formed by plate tectonics. This uplifting of the ocean floor occurs when convection currents rise in the mantle beneath the oceanic crust and create magma where two tectonic plates meet at a divergent boundary. Mid-ocean ridges occur along divergent plate boundaries, where new ocean floor is created as the Earth’s tectonic plates spread apart. As the plates separate, molten rock rises to the seafloor, producing enormous volcanic eruptions of basalt. The speed of spreading affects the shape of a ridge slower spreading rates result in steep, irregular topography while faster spreading rates produce much wider profiles and more gentle slopes.
Answer:
<em>0.45 N</em>
Explanation:
<em>Let Recall that,</em>
<em> The power formula is: </em>
<em> P = E²/R </em>
Let A = the magnetic field
<em>Let L = length of wire = 9.00cm = 0.09 m </em>
let R = resistance of wire = 0.320 Ω
let v = velocity of the wire = 4 m/s
<em>Let E = across the wire voltage </em>
Let P = the power of the wire = 4.3 W
To Solve for E:
<em>The formula of E = √PR </em>
The Voltage from a magnetic field is given as,
E = vAL
We therefore Use E = E
√PR = vAL
to solve for A,
A= √PR/vL
BA= √4.3(0.32)/(4)(.09) -=0.173
A = 0.173 wA/m²
Let F be the pulling force
Let I be the current in the wire
P = I²R
<em>I = √P/R </em>
F = IAL
F = √P/RAL
F = √4.3/.32(0.173)(.09)
<em>F = 0.45N</em>