Question

A chemist prepares a solution of sodium nitrate (NaNO3) by measuring out 286. umol of sodium nitrate into a 450. mL volumetric flask and filling the flask to the mark with water.Calculate the concentration in mmol/L of the chemist's sodium nitrate solution.

Answer 1

Answer:

Concentration of sodium nitrate solution is 0.636 mmol/L

Explanation:

We know, $1micromol=1\times 10^{-3}mmol$

So, $286.micromol=(286.\times 10^{-3})mmol=0.286mmol$

Concentration in mmol/L is defined as number of mmol of solute dissolved in 1000 mL of solution

Here solute is $NaNO_{3}$

Total volume of solution = Total volume of volumetric flask = 450. mL

Hence concentration of $NaNO_{3}$ solution = $\frac{0.286mmol}{450.mL}\times 1000=0.636mmol/L$

So, concentration of sodium nitrate solution is 0.636 mmol/L