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marusya05 [52]
4 years ago
15

What is the total mass of a mixture of 3.50x10^22 formula units na2so4, 0.500 mol h2o, and 7.23 g agcl?

Chemistry
1 answer:
Crazy boy [7]4 years ago
5 0
Answer is: mass of the mixture is 24,47 g.
1) N(Na₂SO₄) = 3,5·10²².
n(Na₂SO₄) = 3,5·10²² ÷ 6·10²³ 1/mol.
n(Na₂SO₄) = 0,058 mol.
m(Na₂SO₄) = 0,058 mol · 142 g/mol.
m(Na₂SO₄) = 8,24 g.
2) n(H₂O) = 0,500 mol.
m(H₂O) = 0,5 mol · 18 g/mol.
m(H₂O) = 9 g.
3) m(total) = 8,24 g + 9 g + 7,23 g.
m(total) = 24,47 g.
n - amount of substance.
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When this equation is solved, the two values of the unknown are 0.0643 and -0.082

Explanation:

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1.77 * 10^{-2} = \frac{x^2}{0.298 - x}

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Open bracket

0.52746 - 1.77x= 100x^2

Rewrite as:

100x^2 + 1.77x - 0.52746 =0

Using quadratic formula:

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

Where:

a = 100; b = 1.77; c = -0.52746

So, we have:

x = \frac{-1.77 \± \sqrt{1.77^2 - 4*100*- 0.52746 }}{2*100}

x = \frac{-1.77 \± \sqrt{214.1169}}{2*100}

x = \frac{-1.77 \± 14.63}{200}

Split

x = \frac{-1.77 + 14.63}{200}\ or\ x = \frac{-1.77 - 14.63}{200}

x = \frac{12.86}{200}\ or\ x = \frac{-16.40}{200}

x = 0.0643\ or\ x = -0.082

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3 years ago
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tatiyna
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3 years ago
A beaker contains 42.0 mL of carbon tetrachloride ( CCl4 , density is 1.59 g/mL). Determine how many molecules of carbon tetrach
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Answer:

Number of molecules = 2.61  x 10²³

Explanation:

Given:

Volume of tetra-chloride = 42 ml

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Mass = Volume of tetra-chloride x Density

Mass = 42 x 1.59

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0.4337 mole = 0.4337 x Avogadro number

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3 0
3 years ago
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Answer:it’s b

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3 0
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<u>Answer:</u> The temperature of the system will be 1622 K

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where,

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Putting values in above equation, we get:

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Hence, the temperature of the system will be 1622 K

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